How Do You Calculate the Height and Latitude of a Geostationary Satellite?

In summary, the geostationary satellite orbits at the same angular frequency as Earth's rotation, not the same velocity. To calculate the dish necessary to point at the satellite, you need to use the derived formula and find the height of the satellite from the ground.
  • #1
TofuManiac
3
0
1. Homework Statement
This is an question from (NZ) NCEA Scholarship Physics practise paper.
Calculate the height of geostationary satellite and hence calculate the lattidue of a satellite dish that must be placed vertical to point at it.
2. Homework Equations
Earth's rotational velocity = 465.1 m/s
therefore v of satellite = 465.1 m/s
using Fc = Fg
(mvsqr)/r = (GMm)/r
vsqr = GM/r
r = GM/vsqr

3. The Attempt at a Solution
Working so far from me:
geostationary satellite = satellite that orbits at of Earth's rotational velocity.
Earth's rotational velocity = 465.1 m/s
therefore v of satellite = 465.1 m/s
using Fc = Fg
(mvsqr)/r = (GMm)/r
vsqr = GM/r
r = GM/vsqr
= 1.8439x10pwrof9
therefore height of geostationary satellite from surface = r - radius of earth
= 1.8439x10pwrof9 - 6.39x10pwrof6
= 1.8375x10pwrof9 m
= 1.84 x 10pwrof9 m (3s.f.)
(I'm not very sure about the answer, it's quite rediculous)

And I'm having a problem with the second part of the question.
Please help :3
 
Last edited:
Physics news on Phys.org
  • #2
TofuManiac said:
geostationary satellite = satellite that orbits at of Earth's rotational velocity.
Earth's rotational velocity = 465.1 m/s
therefore v of satellite = 465.1 m/s
Careful, a geostationary satellite orbits at the same angular frequency (or period) as Earth's rotation, not the same velocity.


using Fc = Fg
(mvsqr)/r = (GMm)/r
You mean mv2/r=GMm/r2 right?:wink:
[/QUOTE]
 
  • #3
Welcome to PF!

TofuManiac said:
… hence calculate the lattidue of a satellite dish that must be placed vertical to point at it.

Hi TofuManiac! Welcome to PF! :smile:

For the second part, start by saying in words what the diagram would look like.

Remember that if the dish is vertical, then the direction of the satellite must be horizontal :wink:
 
  • #4
Thanks man, I totally forgot the most important fact about the geostationary satellite XD

Working:
so period of orbit = 24hr = 86400s
using derived formula - T = sqroot((4 pi^2 r^3)/(GM))
r comes down to 42250474.3m
therefore height of satellite from ground = 42250474.3 - 6.37x10^6 = 3.60x10^7m (3s.f.)

To Tiny-tim = thanks for the help too XD
Cheers :3
 
Last edited:

FAQ: How Do You Calculate the Height and Latitude of a Geostationary Satellite?

What is circular motion of satellite?

Circular motion of satellite refers to the path that a satellite follows around a larger object, such as a planet or a star, in a circular orbit.

How does a satellite maintain its circular orbit?

A satellite maintains its circular orbit due to the balance between its forward motion, which keeps it from falling into the larger object, and the pull of gravity, which keeps it from flying off into space.

What is the relationship between the speed of a satellite and its distance from the larger object?

The speed of a satellite is directly proportional to its distance from the larger object. This means that as the distance increases, the speed decreases, and vice versa.

How does the mass of the larger object affect the circular motion of a satellite?

The mass of the larger object has a direct effect on the circular motion of a satellite. The larger the mass of the object, the stronger its gravitational pull, and the faster the satellite needs to move to maintain its circular orbit.

What factors can affect the stability of a satellite's circular orbit?

The stability of a satellite's circular orbit can be affected by factors such as atmospheric drag, gravitational pull from other objects, and changes in the mass or speed of the satellite. Additionally, changes in the shape or orientation of the orbit can also impact its stability.

Back
Top