How Do You Calculate the Height and Latitude of a Geostationary Satellite?

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Homework Help Overview

The discussion revolves around calculating the height of a geostationary satellite and the latitude for a satellite dish that must be oriented vertically to point at it. The context is based on a physics problem from an NCEA Scholarship practice paper.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the satellite's orbital velocity and Earth's rotational velocity, with some clarifying that a geostationary satellite matches Earth's angular frequency rather than its linear velocity. There are attempts to derive the height of the satellite using gravitational and centripetal force equations, along with discussions about the orbital period and its implications for height calculations.

Discussion Status

Some participants have provided guidance on the correct interpretation of the orbital mechanics involved, while others have shared their calculations and reasoning. There is an ongoing exploration of the problem, with no explicit consensus reached on the final answer.

Contextual Notes

Participants note the importance of understanding the distinction between angular frequency and linear velocity in the context of geostationary satellites. There are also references to the need for a diagram to visualize the satellite's position relative to the satellite dish.

TofuManiac
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1. Homework Statement
This is an question from (NZ) NCEA Scholarship Physics practise paper.
Calculate the height of geostationary satellite and hence calculate the lattidue of a satellite dish that must be placed vertical to point at it.
2. Homework Equations
Earth's rotational velocity = 465.1 m/s
therefore v of satellite = 465.1 m/s
using Fc = Fg
(mvsqr)/r = (GMm)/r
vsqr = GM/r
r = GM/vsqr

3. The Attempt at a Solution
Working so far from me:
geostationary satellite = satellite that orbits at of Earth's rotational velocity.
Earth's rotational velocity = 465.1 m/s
therefore v of satellite = 465.1 m/s
using Fc = Fg
(mvsqr)/r = (GMm)/r
vsqr = GM/r
r = GM/vsqr
= 1.8439x10pwrof9
therefore height of geostationary satellite from surface = r - radius of earth
= 1.8439x10pwrof9 - 6.39x10pwrof6
= 1.8375x10pwrof9 m
= 1.84 x 10pwrof9 m (3s.f.)
(I'm not very sure about the answer, it's quite rediculous)

And I'm having a problem with the second part of the question.
Please help :3
 
Last edited:
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TofuManiac said:
geostationary satellite = satellite that orbits at of Earth's rotational velocity.
Earth's rotational velocity = 465.1 m/s
therefore v of satellite = 465.1 m/s
Careful, a geostationary satellite orbits at the same angular frequency (or period) as Earth's rotation, not the same velocity.


using Fc = Fg
(mvsqr)/r = (GMm)/r
You mean mv2/r=GMm/r2 right?:wink:
[/QUOTE]
 
Welcome to PF!

TofuManiac said:
… hence calculate the lattidue of a satellite dish that must be placed vertical to point at it.

Hi TofuManiac! Welcome to PF! :smile:

For the second part, start by saying in words what the diagram would look like.

Remember that if the dish is vertical, then the direction of the satellite must be horizontal :wink:
 
Thanks man, I totally forgot the most important fact about the geostationary satellite XD

Working:
so period of orbit = 24hr = 86400s
using derived formula - T = sqroot((4 pi^2 r^3)/(GM))
r comes down to 42250474.3m
therefore height of satellite from ground = 42250474.3 - 6.37x10^6 = 3.60x10^7m (3s.f.)

To Tiny-tim = thanks for the help too XD
Cheers :3
 
Last edited:

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