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Getting a solution that contains 40% iodine

  1. Jun 19, 2006 #1
    For solving this problem?

    Two containers are on the shelf. The first one contains a 30% iodine solution and the other contains an 80% iodine solution. How much of the 30% solution should be used to get 50 liters of a solution that is 40% iodine?

    Thanks for any help.
     
  2. jcsd
  3. Jun 19, 2006 #2
    you should really attepmt the problem before posting here.. but-


    okay... how many litres of the 80% stuff is there.. thats the limiting, otherwise you might as well use 25 litres of it diluted with water to 50 litres


    or if you cant dilute with distilled water, like any reasonable person would... then i suppose i would set the thing to equal 50*.4 then the "thing" as i ahve described it would be .3*x and .8*y

    ...so 50*.4=.3*x plus .8*y

    then you get some limiting somehting or other prob in the equation...
     
    Last edited: Jun 19, 2006
  4. Jun 19, 2006 #3
    I attempted the problem but my freaken fomula kept being weird.. uh weird results

    Ohkay I get it thanks.

    The answer is 40 ^__^
     
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