Getting the wrong multipole for 1st acoustic peak

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SUMMARY

The forum discussion addresses the calculation of the multipole moment for the first acoustic peak in the Cosmic Microwave Background (CMB). The user incorrectly calculates the multipole, finding approximately 293 instead of the expected 200, due to confusion between comoving and physical distances. The correct relationship is established as l = \frac{\pi}{d_{hs}}D, with D approximately 14000 Mpc and d_{hs} approximately 150 Mpc. The user is advised to utilize comoving quantities for accurate results, as confirmed by external sources and previous discussions.

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DoobleD
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I'm trying to do a simple calculation, but there must be something wrong.

The wavelength ##\lambda_1## corresponding to first acoustic peak of the CMB is related to the sound horizon at last scattering, ##d_{hs}##, by :

## \lambda_1 = 2d_{hs} ## (see for instance slide 14 on Wayne Hu PDF slides).

Now, the multipole ##l## of the first acoustic peak can be related to its wavelength and to the distance to last scattering surface, ##D##, by :

##l_1 = \frac{2 \pi}{\lambda_1} D## (see slide 15)

From that I deduce the following equation :

##l_1 = \frac{\pi}{d_{hs}}D##

I find in the litterature that ##D \approx 14000 Mpc##, and ##d_{hs} \approx 150 Mpc##. I plug those values into the previous equation, and I find ##l_1 \approx 293##, which is quite far from the ##l_1 \approx 200## I should get for the first peak. What's wrong ?
 
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I get the values for distance to last scattering surface and sound horizon here. I wonder however if 150 Mpc for the sound horizon is not in comoving coordinates, while I should use the physical distance instead (which I don't know) ?

EDIT : I just realized that at the very end of that WMAP values document, they basically give the exact same formula, ##l = \frac{\pi}{d_{hs}}D##. And with the values they gives, I get ##l = 299##. Why am I not getting 200 ?
 
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I just found the exact same question asked by someone else on physics.stackexchange : https://physics.stackexchange.com/questions/222993/how-is-the-first-acoustic-peak-calculated-in-cmb

The guy also finds ##l \approx 300## instead of 200.
 
I'm back on this issue.

Same problem with again another source. We know that ##\theta_s = 0.0104## (slide 4), and ## l = \pi / \theta_s## (slide 18), so we get ##l = 302## instead of around 200. Exactly the same issue as in the https://redirect.viglink.com/?format=go&jsonp=vglnk_152494367988315&key=6afc78eea2339e9c047ab6748b0d37e7&libId=jgjovf9v010009we000DLcrw2gf0c&loc=https%3A%2F%2Fwww.physicsforums.com%2Fthreads%2Fgetting-the-wrong-multipole-for-1st-acoustic-peak.923207%2F&v=1&out=https%3A%2F%2Fphysics.stackexchange.com%2Fquestions%2F222993%2Fhow-is-the-first-acoustic-peak-calculated-in-cmb&ref=https%3A%2F%2Fwww.physicsforums.com%2Fsearch%2F81044411%2F&title=Getting%20the%20wrong%20multipole%20for%201st%20acoustic%20peak%20%7C%20Physics%20Forums&txt=https%3A%2F%2Fphysics.stackexchange.com%2Fquestions%2F222993%2Fhow-is-the-first-acoustic-peak-calculated-in-cmb post I linked earlier actually.
 
Nevermind, this very question has been already answered here. Thanks to @George Jones.
 

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