Gibbs Free Energy Homework: CaCO3 <-> CaO + CO2

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Discussion Overview

The discussion revolves around calculating the Gibbs Free Energy for the reaction CaCO3 <-> CaO + CO2 at 900K, specifically focusing on the relationship between equilibrium pressure and Gibbs Free Energy, as well as the calculation of the equilibrium constant K.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates Gibbs Free Energy as 5656.3 cal/mol and K as 0.0423, expressing uncertainty about the correctness of these values.
  • Another participant questions the relevance of the equilibrium pressure in the calculations.
  • A different participant asserts that the equilibrium pressure of CO2 is connected to the Gibbs Free Energy of the reaction, suggesting that a higher pressure indicates a favored forward reaction.
  • One participant proposes a method for calculating Gibbs Free Energy using the standard formation values and questions whether the equation delta G = -RTlnK can be used to find K.

Areas of Agreement / Disagreement

The discussion includes differing views on the role of equilibrium pressure in the calculations and whether the proposed methods for calculating Gibbs Free Energy and K are correct. No consensus has been reached.

Contextual Notes

Participants reference various equations and methods for calculating Gibbs Free Energy, but there are unresolved aspects regarding the assumptions and definitions involved in these calculations.

jin.cao
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Homework Statement


CaCO3 <-> CaO + CO2
At 900K, equilibrium pressure of CO2 is 0.0423 atm. Calculate Gibbs Free energy of Reaction and K.

Homework Equations


delta G = -RTlnK

The Attempt at a Solution



delta G = 5656.3 cal/mol
K = 0.0423

I have a feeling that this is incorrect
Could someone confirm/clarify for me

Thanks
 
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I'm not sure what the pressure has to do with it..
 
The equilibrium pressure of CO2 is directly connected to the \Delta G of the reaction. If the forward reaction is strongly favored, the pressure is higher, and vice versa.
 
ok, but does the pressure have anything to do with the calculations?

delta G = [sum(delta G formation, products) - sum(delta G formation, reactants)]

which can all be calculated from table values.

Then the equation:

delta G = -RTlnK can be used to find K

is this correct?
 

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