Girl Climbing Rope: Avg Speed & Work Calculated

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SUMMARY

The discussion focuses on calculating the average speed required for a 55.0 kg student to match the power output of a 200-W lightbulb while climbing a 4.00 m rope. To determine the average speed, the power equation P = W/time is utilized, alongside the kinetic energy equation 1/2Mv_f^2 - 1/2Mv_i^2. The work done by the student is also calculated, providing a comprehensive understanding of the physics involved in the scenario.

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Homework Statement



A 55.0 kg student climbs a 4.00 m long rope and stops at the top.
(a) What must her average speed be in order to match the power output of a 200-W lightbulb?
(M/S)

(b) How much work does she do?
(J)


Homework Equations



Well if i had to guess...they might be

P=W/time total

1/2Mvf^2-1/2mvi^2


The Attempt at a Solution

 
Last edited:
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It's OK to be unsure of the relevant equations but not OK when you only give the question. The forum is here to help you, not to do your homework for you.

So don't be shy; which equations do you even half-suspect may be relevant?
 

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