A standard man climbs 15 m up a vertical rope. How much energy (in cal) is dissipated as heat in a single climb if 23% of the total energy required is used to do the work? (Assume the standard man has a mass of 70 kg.)
Q = mgΔh
The Attempt at a Solution
I used Q = mgΔh and took 23% of that and then converted it to calories and it was not correct. I think I am just not understanding what the question is asking for.