# Give me a function that is piecewise continuous but not piecewise smooth

Give me a function that is piecewise continuous but not piecewise smooth

arildno
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The Weierstrass function should fit the bill, in being everywhere continuous, but nowhere differentiable.

|x| is defined piecewise as abs(x)={-x,x<0; x,x>0} which is continuous but not smooth at x=0. And is perhaps a little bit easier to visualize than a fractal :D

|x| is defined piecewise as abs(x)={-x,x<0; x,x>0} which is continuous but not smooth at x=0. And is perhaps a little bit easier to visualize than a fractal :D

Yeah, but this IS piecewise smooth.

pwsnafu
|x| is defined piecewise as abs(x)={-x,x<0; x,x>0} which is continuous but not smooth at x=0. And is perhaps a little bit easier to visualize than a fractal :D

jmm, the domain of of the function you wrote down is the reals minus 0. So it is irrelevant what the function is doing at the origin.

Further as micromass has noted, even if you define abs(0) = 0, the function will still be piecewise smooth. This is because you can split the domain into $(-\infty,0) \cup [0,\infty)$, and so abs has one sided derivatives of all orders at x = 0.

lavinia