Give the magnitude of the magnetic field that will....... 1. The problem statement, all variables and given/known data Suppose the rod in the figure has mass m = 0.38 kg and length 26 cm and the current through it is I = 40 A. If the coefficient of static friction is us = 0.49, determine the minimum magnetic field B (not necessarily vertical) that will just cause the rod to slide. Give the magnitude of B. Express your answer using two significant digits. 2. Relevant equations F = IBd F = usFN 3. The attempt at a solution Since its just "just beginning to move", I know that the two forces are equal to eachother. So: IBd = usFN IBd = usmg which means that: B = (usmg) / Id I plug in the values (after converting them to standard SI units), and I get .175 T. To two significant figures would be .18. But thats not right, I also tried .17, not that either, .2 was also wrong. I don't know what I'm doing wrong.