Given a Hamiltonian how do you pick the most convenient Hilbert space?

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SUMMARY

The discussion focuses on selecting the appropriate Hilbert space for a Hamiltonian describing a 3D particle in a harmonic oscillator potential in the X,Y plane while being free in the Z direction. The Hamiltonian is defined as H = (Px^2 + Py^2 + Pz^2) / (2m) + 1/2*mω^2(x^2+y^2). The most suitable Hilbert space for this system is identified as L^2((0,r),dr) X {e^(imφ) | m in Z} X L^2(R,dz), which accounts for the symmetries of energy, angular momentum about the z-axis, and linear momentum in the z-direction.

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golnat
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For example, I have a 3D particle that experiences a harmonic oscillator potential only in the X,Y plane for all Z ie. a free particle in the Z direction. This seems like cylindrical coordinates but I'm not sure how to express the Hilbert space if I want to be able to describe states and eigenvalues.

H = (Px^2 + Py^2 + Pz^2) / (2m) + 1/2*mω^2(x^2+y^2)

I know that the energies will be characterized by the two harmonic oscillator dimension quantum numbers and also by the momentum in the z-direction, but what is the formal way to describe the Hilbert space?

Thanks in advance.
 
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In ordinary QM (as opposed to QFT) all Hilbert spaces are equivalent, so you don't have to care.
Maybe you mean the range of definition?
 
I'm studying for my preliminary exam for grad school, and I have a practice problem that gives this Hamiltonian. The first part asks about the symmetries of the hamiltonian. I said energy, angular momentum about the z-axis and linear momentum in the z-direction. The next part asks, "Describe the most convenient Hilbert space to use for describing states and eigenvalues of this system, and describe why."
 
Technically the existing symmetries (such as space-time ones) would help you get a suitable Hilbert space starting from L^(R^n), n = dof. For the uniparticle Hamiltonian in post #1, the Hilbert space would be L^2((0,r),dr) X {e^(im\phi) | m in Z} X L^2 (R,dz).
 
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