(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

If 0.025 g of Fe(OH)3 is added to 3.84 L of water, what mass will dissolve? Ksp is 2.8E-39.

2. Relevant equations

Ksp = [x][x]

n= m/M

3. The attempt at a solution

I believe in this question that the starting mass is deemed irrelevant (although now i am starting to believe that is required to do something)

So, Fe(OH)3 = Fe + 3OH, this means that our Ksp equation will be

(x)(3x)^3 = 2.8E-39

So we can simplify to 27x^4 = 2.8E-39, solve for x to get the concentration, which will yield 1.009E-10 mol/L.

Now multiply by volume:

1.009E-10 mol/L * 3.84 L = 3.875E-10 mol * 106.8670 g/mol = 4.14E-8 grams. This is what i am getting and this incorrect. Can someone explain why, and also can someone explain if we have to use the starting mass somehow.

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# Homework Help: Given a mass, how much mass of this solid will dissolve in w

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