Mass of oxygen in 2.5 × 10² g of CaCO₃

[Sace Ver]

Homework Statement

What would be the mass of oxygen in 2.5 x 10² g in CaCO₃?
Given:
Mass 2.5 x 10²
Molar Mass of CaCO₃ which is 100.09 g/mol.

Homework Equations

m_o=molar mass x number of o

The Attempt at a Solution

m_o=100.09 g/mol x 3
m_o=300.27 g of oxygen

Can someone tell me if I got this right? Thank you.

 

[SteamKing]

Homework Statement

What would be the mass of oxygen in 2.5 x 10² g in CaCO₃?
Given:
Mass 2.5 x 10²
Molar Mass of CaCO₃ which is 100.09 g/mol.

Homework Equations

m_o=molar mass x number of o

The Attempt at a Solution

m_o=100.09 g/mol x 3
m_o=300.27 g of oxygen

Can someone tell me if I got this right? Thank you.

If you start with 250 g of CaCO₃, how can you have 300.27 g of oxygen?

 

[SteamKing]

Homework Statement

What would be the mass of oxygen in 2.5 x 10² g in CaCO₃?
Given:
Mass 2.5 x 10²
Molar Mass of CaCO₃ which is 100.09 g/mol.

Homework Equations

m_o=molar mass x number of o

The Attempt at a Solution

m_o=100.09 g/mol x 3

Here, you are assuming that all 100 g/mol is oxygen, which it is clearly not.

You need to figure out how many moles of CaCO₃ there are in 250 g of the substance.

 

[Borek]

Assuming one mole of CaCO₃ - how many moles of O (atomic oxygen)?

 

[Sace Ver]

Here, you are assuming that all 100 g/mol is oxygen, which it is clearly not.

You need to figure out how many moles of CaCO₃ there are in 250 g of the substance.

And then divide by 3 bc there is 3 atoms of oxygen?

 

[SteamKing]

And then divide by 3 bc there is 3 atoms of oxygen?

There will be 3 moles of oxygen atoms in each mole of CaCO₃.