The discussion revolves around calculating the mass of oxygen in a given mass of calcium carbonate (CaCO3). Participants explore the relationship between the molar mass of CaCO3 and the number of oxygen atoms present in the compound, focusing on the correct approach to determine the mass of oxygen from the total mass of CaCO3.
Participants do not reach a consensus, as there are competing views on the correct method for calculating the mass of oxygen from the mass of CaCO3. Some participants challenge the initial calculation and propose alternative steps, indicating that the discussion remains unresolved.
Participants express uncertainty regarding the assumptions made in the calculations, particularly about the distribution of mass among the constituent elements of CaCO3 and the need to convert mass to moles before further calculations.
If you start with 250 g of CaCO3, how can you have 300.27 g of oxygen?Sace Ver said:Homework Statement
What would be the mass of oxygen in 2.5 x 102 g in CaCO3?
Given:
Mass 2.5 x 102
Molar Mass of CaCO3 which is 100.09 g/mol.
Homework Equations
mo=molar mass x number of o
The Attempt at a Solution
mo=100.09 g/mol x 3
mo=300.27 g of oxygen
Can someone tell me if I got this right? Thank you.
Here, you are assuming that all 100 g/mol is oxygen, which it is clearly not.Sace Ver said:Homework Statement
What would be the mass of oxygen in 2.5 x 102 g in CaCO3?
Given:
Mass 2.5 x 102
Molar Mass of CaCO3 which is 100.09 g/mol.
Homework Equations
mo=molar mass x number of o
The Attempt at a Solution
mo=100.09 g/mol x 3
And then divide by 3 bc there is 3 atoms of oxygen?SteamKing said:Here, you are assuming that all 100 g/mol is oxygen, which it is clearly not.
You need to figure out how many moles of CaCO3 there are in 250 g of the substance.
There will be 3 moles of oxygen atoms in each mole of CaCO3.Sace Ver said:And then divide by 3 bc there is 3 atoms of oxygen?