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Calculating mass of oxygen in CaCO3...

  1. Nov 9, 2015 #1
    1. The problem statement, all variables and given/known data
    What would be the mass of oxygen in 2.5 x 102 g in CaCO3?
    Given:
    Mass 2.5 x 102
    Molar Mass of CaCO3 which is 100.09 g/mol.

    2. Relevant equations
    mo=molar mass x number of o

    3. The attempt at a solution
    mo=100.09 g/mol x 3
    mo=300.27 g of oxygen

    Can someone tell me if I got this right? Thank you.
     
    Last edited by a moderator: Nov 9, 2015
  2. jcsd
  3. Nov 9, 2015 #2

    SteamKing

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    If you start with 250 g of CaCO3, how can you have 300.27 g of oxygen?
     
  4. Nov 9, 2015 #3

    SteamKing

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    Here, you are assuming that all 100 g/mol is oxygen, which it is clearly not.

    You need to figure out how many moles of CaCO3 there are in 250 g of the substance.
     
  5. Nov 10, 2015 #4

    Borek

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    Assuming one mole of CaCO3 - how many moles of O (atomic oxygen)?
     
  6. Nov 10, 2015 #5
    And then divide by 3 bc there is 3 atoms of oxygen?
     
  7. Nov 10, 2015 #6

    SteamKing

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    There will be 3 moles of oxygen atoms in each mole of CaCO3.
     
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