Given a tangent line, find f(x)

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The discussion revolves around a calculus problem involving a tangent line to the function y = f(x) at the point (4,3) that passes through (0,2). The user correctly identifies the slope of the tangent line as 1/4 and seeks to find f(x) and f'(4). It is clarified that f(4) is already known as 3, based on the given point. The conversation highlights the importance of understanding ordered pairs in relation to calculus concepts. Ultimately, the user is reminded that f'(4) is equal to the slope of the tangent line, which is 1/4.
mbrmbrg
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I have a homework problem as follows:

If the tangent line to y = f(x) at (4,3) passes through the point (0,2), find f(4) and f'(4).

Using the slope formula and the point-slope formula, I found that the equation of the given tangent line is y = 1/4x + 2.

Now I want to find f(x) so I can actually answer the question.

I thought I might be able to solve for f(x) using the equation

f'(a)= lim [f(x+h) - f(x)]/h
h-->0

and subsituting 1/4 for f'(a), but I can't get any farther than setting that up.

help? please?
thanks!
 
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You don't need f(x) to know what f(4) is. You're already given f(4)
 
Thank you!
I have to remember that learning calculus does not mean forgetting the very first rules of reading ordered pairs, don't I...
 
mbrmbrg said:
Thank you!
I have to remember that learning calculus does not mean forgetting the very first rules of reading ordered pairs, don't I...
Well put! :approve:
 
what will be f'(4)?

0?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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