Given height find how fast its moving

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Homework Help Overview

The problem involves a seagull dropping a shell from a height of 6 meters and seeks to determine the speed of the shell upon impact with the ground. The subject area pertains to kinematics and motion equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the appropriate kinematic equations to use given the parameters of the problem, including initial velocity, distance, and acceleration due to gravity. There is an exploration of different equations and attempts to clarify which is suitable without time being provided.

Discussion Status

The discussion has progressed with participants providing guidance on the correct kinematic equations to apply. One participant has indicated they figured out the solution, although the specifics of the resolution are not detailed in the discussion.

Contextual Notes

There is a noted constraint regarding the lack of time as a given variable, which influences the choice of equations discussed. Participants are navigating the implications of this limitation in their reasoning.

kmiller
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given height find how fast its moving...

Homework Statement



Seagulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells. If a seagull drops a shell from rest at a height of 6 m, how fast is the shell moving when it hits the rocks?
find m/s

The Attempt at a Solution



6m/9.8=58.8 wrong
i can't figure it out help please
 
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What equation did you attempt to use?

Are you not aware of the kinematics equations?
 


I am using motion equations, Vf=Vi+at
 


But you're not given the time. You're only given the initial velocity, the distance, and you know the acceleration due to gravity. That is not the correct formula to use. What other formulas are there for kinematics?
 


VF2=Vi2+2a+(delta)

or

Xf=Xi=Vit=.5at2
 


The first equation is correct.

Vf^2 = Vo^2 + 2ad

You have to use the equation that has the terms that you're given. You're not given time and so you can't use any other equation in this situation. Now are you able to solve the problem?
 


Yes if figured it out thanks a lot
the answer was 10.844 m/s
 

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