GPE and KE - Help with AS Physics Coursework

  • Thread starter Thread starter meawinner
  • Start date Start date
  • Tags Tags
    Gpe
Click For Summary
When an object is lifted, it gains gravitational potential energy (GPE) calculated as GPE = mgh, which depends on its height. As the object falls, this GPE gradually converts into kinetic energy (KE), not all at once, maintaining energy conservation throughout the fall. The total energy, which is the sum of GPE and KE, remains constant at all times during the object's descent. Misunderstandings about the relationship between GPE and KE being inversely proportional are clarified; they are not inversely related but rather part of a constant sum. Understanding these principles is crucial for accurately completing AS physics coursework.
meawinner
Messages
11
Reaction score
0
GPE and KE...please help! argh

Hi I am just finishing my AS physics coursework and just as i thought i understood it someone tells me something else. When you pick up an object i understand that it gains GPE and the amount of this depends on the height it is picked up to, hence GPE = mgh. But when you drop the object what happens to the energy? Does it all suddenly convert to KE, or when it is falling does the GPE gradually turn to KE?

In my coursework i calculated GPE and KE, assuming they should be roughly the same values and they were but then some1 said to me that they should be inversely proportional to each other.

Can some1 please help me thank-you.

meawinner
 
Physics news on Phys.org
just think about conservation of energy. when the object is falling, the height changes, by virtue of energy conservation, the object gains kinetic energy.
 
If you lift a ball to some heigth h, you obtain a potential energy due to gravity that is equal to mgh. When the ball drops, the energy is gradually converted to KE, not all at once. To emphasize this point, imagine dropping the ball from heigth h. A friend catches the ball at height h/2. Since we already know the formula for potential energy due to gravity, our new potential would be equal to mgh/2. The ball still maintains an energy potential that was not converted to kinectic. All the potential energy is converted to kinetic energy at a time (only at the instantaneous moment right before impact) when h=0 after the point of release.
 
Last edited:
meawinner said:
In my coursework i calculated GPE and KE ...
some1 said to me that they should be inversely proportional to each other.
meawinner

As are implied by Dr Transport's and quantum mechanic's replies, the conversion of potential energy into kinetic energy (or vice versa in other situations) is a gradual process.

When we have energy conservation, it means that the SUM of kinetic energy and potential energy remains equal at all times.

Those who told you that the kinetic energy should be inversely proportional to the potential energy are totally wrong; they haven't learned the elementary distinction between a sum and a product.
 
The sum of the energys must remain constant. (this is a no loss system of course!)

So Total Energy = Potential Energy + Kinetic Energy

This is true at each point of the fall.
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
6
Views
2K
Replies
7
Views
5K
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K