Gradient of an inverse vector function?

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The discussion revolves around finding the gradient of the function f(𝑥) = |𝑥|^r, where 𝑥 is a vector in ℝ^n and r is a real number. The user expresses confusion about the concept of an inverse vector function and its implications for calculating the gradient. They clarify that since the function outputs a scalar, the gradient can be computed using partial derivatives. The example provided illustrates how to derive the first component of the gradient by applying the chain rule. The conversation emphasizes the importance of understanding vector functions and their gradients in multivariable calculus.
CAF123
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Homework Statement


Consider f(\vec{x}) = |\vec{x}|^r, where \vec{x} \in ℝ^n and r \in ℝ.
Find \vec{∇}f

The Attempt at a Solution


I know a vector function maps real numbers to a set of vectors, but here I believe we have the opposite. (inverse of a vector function, assuming inverse exists?)
I am unsure of where to go next.
 
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Assuming the usual Euclidean norm on ℝ^n, the output is just a scalar. Computing the gradient, then, is a matter of taking partial derivatives. For example, the first component of the gradient is the partial of f with respect to x_1. If f= (sqrt(x_1^2 + ... + x_n^2))^r = (x_1^2 + ... + x_n^2) ^ (r/2) then the partial with respect to x_1 is r/2(x_1^2 + ... + x_n^2)^(r/2-1)*(2x_1). Continuing in this fashion gives the gradient.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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