- #1

BrownBoi7

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The graph in the picture attached describes the motion of a 500.0 g cart for the first 60 seconds of its motion.

1. Calculate how far the cart moves during the fi rst 25 seconds of motion.

2. Indicate the time intervals during which the cart has a non-zero acceleration.

3. Calculate the acceleration of the cart at 35 seconds.

4. Indicate all times during which the cart is at rest.

5. Calculate how far the cart is from its starting location after 60 seconds.

6. Calculate the additional time required for the cart to arrive back at its initial position if it continues to move at 50 m/s as indicated on the graph.

My attempt:

1. area of triangle + area of rectangle = total displacement in first 25 seconds = distance

1000 m + 500 m = 1500 m

2. (0,20) and (30,45)

3. 50-100/5 = -50/5 = -5 m/s^2

4. At t = 0 and t = 40

5. Total area covered? 1000 m + 1000 m + 500 m + 125 m + 750 m = 3375 m

6. I did not understand this question. Do i just get the area (distance) and speed is given. So i can get the time taken? I don't know why they would give the

I haven't used it answering any of the questions--that kinda puts me in doubt as to if I answered them correctly.

Can somebody please review them and let me know where I'm wrong?

Thanks!

1. Calculate how far the cart moves during the fi rst 25 seconds of motion.

2. Indicate the time intervals during which the cart has a non-zero acceleration.

3. Calculate the acceleration of the cart at 35 seconds.

4. Indicate all times during which the cart is at rest.

5. Calculate how far the cart is from its starting location after 60 seconds.

6. Calculate the additional time required for the cart to arrive back at its initial position if it continues to move at 50 m/s as indicated on the graph.

My attempt:

1. area of triangle + area of rectangle = total displacement in first 25 seconds = distance

1000 m + 500 m = 1500 m

2. (0,20) and (30,45)

3. 50-100/5 = -50/5 = -5 m/s^2

4. At t = 0 and t = 40

5. Total area covered? 1000 m + 1000 m + 500 m + 125 m + 750 m = 3375 m

6. I did not understand this question. Do i just get the area (distance) and speed is given. So i can get the time taken? I don't know why they would give the

**mass**of the object?I haven't used it answering any of the questions--that kinda puts me in doubt as to if I answered them correctly.

Can somebody please review them and let me know where I'm wrong?

Thanks!