Graph of Electric Potential vs. Function

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Homework Help Overview

The discussion revolves around creating a graph of electric potential versus distance, specifically starting from a designated point and moving in a clockwise direction. The original poster expresses uncertainty about how to represent voltage values on the graph, particularly regarding the reference point for measuring voltage differences.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster questions how to assign voltage values on the graph, particularly whether the starting point can be considered as having zero voltage. They also inquire about representing the voltage across a resistor in relation to the graph.

Discussion Status

The discussion is ongoing, with participants attempting to clarify the original poster's questions about voltage representation and the implications of choosing a reference point. There is no explicit consensus yet, as participants are exploring different aspects of the problem.

Contextual Notes

There are issues with accessing the provided link, which may hinder the discussion. Participants are attempting to resolve this while discussing the problem context.

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copy and paste the url onto your address bar

http://www.imagestation.com/picture/sraid140/p1b9d403a3d9390dd3e7c43eaa1b6e0c8/f6ed3314.jpg

the question asks me to draw a graph of electric potential vs distance starting from from point g (starting at g and going around in a clockwise manner).

i am not sure how to proceed. i mean i know voltage is only meaningful if it is measured as a difference between two points. for instance, i know the voltage across the 10 ohm resistor is 0.09009V, which is the voltage at b relative to a. On the graph would i just have b = 0.09009V? If i start at g, does it mean that g has a voltage of zero?

Thanks.
 
Last edited by a moderator:
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Linky no worky ("page not found").
 
sorry.. about the copying and pasting thing. just click on the link and it should work.
 
That didn't work either ("forbidden"). Maybe it'll work for other people.
 

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