Graph of P(x) Under |y| Transformations: a & b

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SUMMARY

The discussion focuses on the behavior of the linear function P(x) = 3x + 4 under the transformation y = |P(x)|. When y ≥ 0, the graph remains unchanged as it is above the x-axis, reflecting the positive values of P(x). However, when y < 0, the graph is reflected across the x-axis, converting negative values of P(x) into positive values, thus creating a V-shaped graph. This transformation effectively ensures that all output values of y are non-negative.

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QS: Explain how the graph P(x)=3x+4 behaves under the transformation y=|P(x)| when:
a) y\ge0
b) y<0

I'm not sure how to explain this in words.Thank You!
 
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twicesana said:
QS: Explain how the graph P(x)=3x+4 behaves under the transformation y=|P(x)| when:
a) y\ge0
b) y<0

I'm not sure how to explain this in words.Thank You!
What is |3|?

What is |-3|?

So given [math]y \geq 0[/math] what happens to |y|? etc.

-Dan
 
transformation sketch ...
 

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