Graphical analysis, vx, ax, and xf problems

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SUMMARY

This discussion focuses on solving problems related to graphical analysis of motion, specifically velocity and displacement calculations. Key problems include determining the final velocity of a car under constant acceleration, calculating the distance traveled by an object with changing speeds, and finding the height of a building based on the time taken for a ball to hit the ground. The correct answers provided include a final velocity of 45 m/s, a distance of 39 m, and a building height of 30 m. Additionally, the displacement over a time interval is determined through the area under the velocity-time graph.

PREREQUISITES
  • Understanding of kinematic equations for linear motion
  • Familiarity with velocity and acceleration concepts
  • Knowledge of graph interpretation, specifically velocity vs. time graphs
  • Basic calculus principles, specifically integration for area under curves
NEXT STEPS
  • Study kinematic equations in detail, focusing on constant acceleration scenarios
  • Learn how to calculate displacement using integration techniques
  • Explore graphical analysis of motion, particularly velocity-time graphs
  • Review precision in measurements and significant figures in physics
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Students studying physics, educators teaching motion concepts, and anyone interested in mastering kinematics and graphical analysis of motion.

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1.) A car travels at 15 m/s for 10s. It then speeds up with a constant acceleration of 2.00 m/s^2 for 15s. At the end of this time, what is its velocity?

My answer: Vxf= 45 m/s

2.) An object is moving in a straight line with constant acceleration. Initially it is traveling at 16 m/s. Three seconds later it is traveling at 10 m/s. How far does it move during this time?

My answer: 39m

3.) A ball is thrown downward from the top of a building with an initial speed of 25 m/s. It strikes the ground after 2.0s. How high is the building?

My answer: 30m

4.) I can't draw a graph on here, so I'll describe it to the best of my abilities. It is a velocity versus(m/s) vs. time (s) graph.

The graph starts at the origin. At 2.0s, velocity increases 20 m/s. From 2.0 to 4.0 seconds, velocity is constant at 20m/s. From 4.0 to 6.0s, velocity is decreasing by 20 m/s. At 6.0 to 8.0s, velocity is decreasing another 20 m/s.

question: What is the displacement from 0 to 8.0s?

My answer: Honestly, I didn't know how to approach this one. All i did was I added up and subtracted...and got 20m.

5.) Which student used the least precise scale?
A. 49.06
B. 49
C. 50
D. 49.2
 
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mark9159 said:
1.) A car travels at 15 m/s for 10s. It then speeds up with a constant acceleration of 2.00 m/s^2 for 15s. At the end of this time, what is its velocity?

My answer: Vxf= 45 m/s

2.) An object is moving in a straight line with constant acceleration. Initially it is traveling at 16 m/s. Three seconds later it is traveling at 10 m/s. How far does it move during this time?

My answer: 39m

3.) A ball is thrown downward from the top of a building with an initial speed of 25 m/s. It strikes the ground after 2.0s. How high is the building?

My answer: 30m

4.) I can't draw a graph on here, so I'll describe it to the best of my abilities. It is a velocity versus(m/s) vs. time (s) graph.

The graph starts at the origin. At 2.0s, velocity increases 20 m/s. From 2.0 to 4.0 seconds, velocity is constant at 20m/s. From 4.0 to 6.0s, velocity is decreasing by 20 m/s. At 6.0 to 8.0s, velocity is decreasing another 20 m/s.

question: What is the displacement from 0 to 8.0s?

My answer: Honestly, I didn't know how to approach this one. All i did was I added up and subtracted...and got 20m.

5.) Which student used the least precise scale?
A. 49.06
B. 49
C. 50
D. 49.2

For question 4. Since displacement is the integral of velocity, you should calculate the area under the velocity curve, from 0 to 8 secods.
 

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