Graphing a Rotated Conic on a Graphing Calculator

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Homework Help Overview

The discussion revolves around graphing a conic section defined by the equation x^2 + xy + y^2 = 10 using a graphing utility. Participants are exploring the angle of rotation for the axes and the challenges of graphing the rotated function.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method to find the angle of rotation and the transformation of the equation into a quadratic form for y. There are attempts to graph the conic using a graphing calculator, with some participants questioning the feasibility of graphing implicit functions.

Discussion Status

The discussion includes various attempts to solve the quadratic equation derived from the conic. Some participants report encountering imaginary solutions and calculator errors, while others provide corrections and suggestions for rewriting the equation. There is no explicit consensus on the best approach yet, but guidance has been offered to address the errors encountered.

Contextual Notes

Participants are working under the constraint that their graphing calculators cannot graph implicit functions directly, which complicates their efforts to visualize the rotated conic. There are also indications of potential misunderstandings regarding the setup of the quadratic formula.

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Homework Statement


Use a graphing utility to graph the conic. Determine the angle through which the axis are rotated.

[tex]x^2+xy+y^2=10[/tex]

Homework Equations


[tex]\cot2\theta=\frac{A-C}{B}[/tex]
[tex]x=x'\cos\theta-y'\sin\theta[/tex]
[tex]y=x'\sin\theta+y'\cos\theta[/tex]

The Attempt at a Solution



I can find the angle of rotation to be 45 degrees and I know the equation in terms of x' y' is.

[tex]\frac{(x')^2}{\frac{20}{3}}+\frac{(y')^2}{20}=1[/tex]

However I don't know how to graph the rotated function. My graphing calculator can not graph implicit functions. I can get function in terms of x',y' in terms of y' and graph that, but that won't be on an x',y' axis on my calculator, only an x,y axis. How can I graph the rotated function on a calculator?
 
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To graph the conic using a graphing utility, you need to solve the conic for y. Rewrite the equation as a quadratic equation to y (the x's will be part of the coefficients):
[tex]\begin{aligned}<br /> x^2 + xy + y^2 &= 10 \\<br /> y^2 + (x)y + (x^2 - 10) &= 0 \\<br /> \end{aligned}[/tex]
Use the quadratic formula with [tex]a = 1[/tex], [tex]b = x[/tex], and [tex]c = (x^2 - 10)[/tex].69
 
eumyang said:
To graph the conic using a graphing utility, you need to solve the conic for y. Rewrite the equation as a quadratic equation to y (the x's will be part of the coefficients):
[tex]\begin{aligned}<br /> x^2 + xy + y^2 &= 10 \\<br /> y^2 + (x)y + (x^2 - 10) &= 0 \\<br /> \end{aligned}[/tex]
Use the quadratic formula with [tex]a = 1[/tex], [tex]b = x[/tex], and [tex]c = (x^2 - 10)[/tex].


69

I did that and I wind up getting an imaginary answer. My calculator comes up with errors.

[tex]x=\frac{-x\pm\sqrt{-3x^2-40}}{2}[/tex]
 
themadhatter1 said:
I did that and I wind up getting an imaginary answer. My calculator comes up with errors.

[tex]x=\frac{-x\pm\sqrt{-3x^2-40}}{2}[/tex]

(I assume you meant to type "y" on the left side.) Should be + 40, not - 40. Underneath the square root you should have set up
[tex]\sqrt{x^2 - 4(1)(x^2 - 10)}[/tex]
69
 
Last edited:
eumyang said:
(I assume you meant to type "y" on the left side.) Should be + 40, not - 40. Underneath the square root you should have set up
[tex]\sqrt{x^2 - 4(1)(x^2 - 10)}[/tex]



69

Thanks for all your help. It works fine now.
 

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