Graphing complex functions(the image)

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Graphing complex functions, such as f(z) = z^2 where z = x + iy, involves mapping from the real plane to a complex plane. The function can be expressed in terms of its real and imaginary components: Re(z^2) = x^2 - y^2 and Im(z^2) = 2xy. This creates a mapping from R² to R², necessitating a four-dimensional representation. A common approach is to visualize how lines in the xy-plane transform into curves in the uv-plane, with specific examples illustrating this mapping. Understanding these transformations is crucial for effectively graphing complex functions.
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I'm really unsure how to go about graphing a complex function. Like, f(z) = z^2, where z = x+iy.

This ISN'T a homework problem, but I'm studying for an exam and that's an example in a book I'm reading and it says "the image of this function" and goes on explaining some things relevant to the drawing, but there doesn't seem to be a systematic way to go about doing this.

Thanks.
 
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Find the real and imaginary images of the mapping.

Since z= x+iy then z^2 = x^2-y^2+2ixy.

Thus we have \Re(z^2) = x^2-y^2 \text{ and } \Im(z^2) = 2xy

Now think of this as a mapping from \mathbb{R}^2 \rightarrow \mathbb{R}^2 under the function f(x,y) = (x^2-y^2, 2xy)
 
Which means, of course, that you would need a four-dimensional graph!

What is often done is to take u(x,y)+ iv(x,y)= f(z)= x+ iy. Draw some lines in an xy-plane and show what those are mapped into in the uv-plane.
For example, with f(z)= f(x+iy)= (x2-y2+ i(2xy), the
horizontal line y= 0 is mapped into u= x2, v= 0 which is just the vertical line v= 0. The horizontal line y= 1 is mapped into u= x2-1, v= 2x so u= v2/4, a parabola.
 

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