Graphing complex functions(the image)

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SUMMARY

The discussion focuses on graphing complex functions, specifically the function f(z) = z^2, where z = x + iy. The transformation results in the real part \Re(z^2) = x^2 - y^2 and the imaginary part \Im(z^2) = 2xy, leading to a mapping from \mathbb{R}^2 to \mathbb{R}^2. To visualize this mapping, one can represent it in a four-dimensional graph, or alternatively, plot the images of lines in the xy-plane onto the uv-plane, demonstrating how specific lines transform under the function.

PREREQUISITES
  • Understanding of complex numbers and their representation (z = x + iy)
  • Familiarity with functions and mappings in two dimensions
  • Knowledge of real and imaginary parts of complex functions
  • Basic graphing skills in Cartesian coordinates
NEXT STEPS
  • Study the visualization techniques for complex functions using software like GeoGebra
  • Learn about the mapping of complex functions in higher dimensions
  • Explore the properties of complex mappings and their geometric interpretations
  • Investigate other complex functions, such as f(z) = e^z and their graphs
USEFUL FOR

Students preparing for exams in complex analysis, mathematicians interested in visualizing complex functions, and educators teaching advanced mathematics concepts.

desaila
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I'm really unsure how to go about graphing a complex function. Like, f(z) = z^2, where z = x+iy.

This ISN'T a homework problem, but I'm studying for an exam and that's an example in a book I'm reading and it says "the image of this function" and goes on explaining some things relevant to the drawing, but there doesn't seem to be a systematic way to go about doing this.

Thanks.
 
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Find the real and imaginary images of the mapping.

Since [tex]z= x+iy[/tex] then [tex]z^2 = x^2-y^2+2ixy[/tex].

Thus we have [tex]\Re(z^2) = x^2-y^2 \text{ and } \Im(z^2) = 2xy[/tex]

Now think of this as a mapping from [tex]\mathbb{R}^2 \rightarrow \mathbb{R}^2[/tex] under the function [tex]f(x,y) = (x^2-y^2, 2xy)[/tex]
 
Which means, of course, that you would need a four-dimensional graph!

What is often done is to take u(x,y)+ iv(x,y)= f(z)= x+ iy. Draw some lines in an xy-plane and show what those are mapped into in the uv-plane.
For example, with f(z)= f(x+iy)= (x2-y2+ i(2xy), the
horizontal line y= 0 is mapped into u= x2, v= 0 which is just the vertical line v= 0. The horizontal line y= 1 is mapped into u= x2-1, v= 2x so u= v2/4, a parabola.
 

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