Graphing Linear Equations: Finding Intercepts

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To graph the linear equation y = 3x - 2, start by finding the y-intercept by setting x to zero, resulting in the point (0, -2). Next, determine the x-intercept by setting y to zero, which gives the point (2/3, 0). With these two points identified, plot them on the graph and connect them with a straight line. The slope of 3 indicates that the line will rise as it moves from left to right. This method effectively illustrates the linear relationship defined by the equation.
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How would I go about graphic this?

y = 3x - 2
 
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As you alluded to in the subject of your post, a good way to graph the equation is to find the y intercept; and graph from there knowing the slope is 3. So set x to zero and determine the y intercept that way, then simply use the slope's ratio (3/1) and remember "rise over run".
 
Or you can realize it is a linear equation and just take any two points, graph them, and connect them with a straight line.
 
all you do is find the two intercepts and join them together...
remember that to find...
y-intercept, let x = 0 and
x-intercept, let y = 0...

so y-intercept = y = 3(0) - 2
y-int = -2
therefore ... (0,-2)

and x-intercept = 0 = 3x-2
3x = 2
x = (2/3)

(2/3,0)

so then you put a dot on those points and draw a line.
the line should be increasing since you know that the gradient is positive.
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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