Graphing r = 1 - cos(theta) (polar coordinates

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SUMMARY

The discussion focuses on graphing the polar equation r = 1 - cos(θ), which exhibits asymmetric behavior around the y-axis. Users express confusion regarding the graph's shape compared to the simpler r = sin(θ). Key observations include that at θ = 0, r equals 0, and as θ increases to π, r increases before decreasing again as θ approaches 2π. The graph's complexity stems from the nature of the cosine function and its impact on the radius in polar coordinates.

PREREQUISITES
  • Understanding of polar coordinates and their graphical representation.
  • Knowledge of trigonometric functions, specifically cosine.
  • Ability to interpret and create graphs based on mathematical equations.
  • Familiarity with the unit circle and its relation to trigonometric values.
NEXT STEPS
  • Study the properties of polar equations and their graphs.
  • Learn how to convert polar equations to Cartesian coordinates.
  • Explore the behavior of other trigonometric functions in polar coordinates.
  • Practice graphing various polar equations using software tools like Desmos or GeoGebra.
USEFUL FOR

Students studying mathematics, particularly those focusing on polar coordinates and trigonometry, as well as educators looking for insights into teaching these concepts effectively.

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Homework Statement


Okay the graph SHOULD look like this.
http://jwilson.coe.uga.edu/EMAT6680Fa11/Chun/11/21.png
I can't make sense of this at all. It looks so weird. Why does it bend around the y-axis in such an asymmetric way? I just graphed r = sin(θ) with ease by making a table of r vs θ
and graphing it... but this doesn't seem to be as easy?
 
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A plot of the problem for ##\theta \in [0, 2\pi]## : http://gyazo.com/6811fa8ed2ba867fb9f16d49c3feea09

Notice for ##\theta = 0##, ##cos(\theta) = 1## so that ##r = 0##.

Now, as you increase ##\theta##, notice that ##cos(\theta)## will decrease until ##\theta = \pi## and ##r## will increase.

Then, ##cos(\theta)## begins to increase again and ##r## will start decreasing until ##\theta = 2\pi##.
 

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