Graphs of a vs. t, v vs. t, and d vs. t ?

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SUMMARY

The discussion focuses on deriving the graphs of velocity (v vs. t) and displacement (d vs. t) from a given acceleration (a vs. t) graph. Key relationships include that acceleration is the derivative of velocity (a = dv/dt) and velocity is the derivative of displacement (v = dx/dt). To create the velocity graph, one must estimate the area under the acceleration curve, while the displacement graph is derived from the area under the velocity curve. The discussion emphasizes the importance of understanding these integral relationships to accurately interpret motion graphs.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically integration.
  • Familiarity with kinematic equations and their relationships.
  • Knowledge of graph interpretation in physics.
  • Ability to analyze motion graphs and their derivatives.
NEXT STEPS
  • Study the integral calculus concepts related to motion graphs.
  • Learn how to apply kinematic equations in practical scenarios.
  • Explore graphing techniques for visualizing acceleration, velocity, and displacement.
  • Review resources on motion graphs, such as HyperPhysics links provided in the discussion.
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Students in physics, educators teaching kinematics, and anyone interested in understanding the relationships between acceleration, velocity, and displacement through graphical analysis.

IamHenry
Graphs of a vs. t, v vs. t, and d vs. t ?

Plese help !

I am given a graph of a vs. t
How do i use it to determine the other graphs:
v vs. t
d vs. t
 
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You haven't supplied enough information. What are the relationships between the variables defined by the letters a,t,v,d?
 
If you have the equations, just plug in a few points and go.

If you have one equation, you integrate to get the others... but like mathman said, you haven't given us enough information.
 
i am not given any equations
i am only given the graph of a vs. t
btw
a=acceleration
t=time
v=velocity
d=displacement
please help
thx
 
You need to use the basic relationships between the quanities.

a= dv/dt => The acceleration determines the slope of the velocity graph. So a constant acceleration line means an increasing velocity, Acceleration = 0 means a constant velocity. You must study the graphs you are given and piece together the various graphs.

Remember that v = dx/dt so you can do the same thing with the velocity line to create a displacement graph.

With that said this is off to homework.
 
v = [inte] a dt

d = [inte] d dt
 
If it's not a very screwed up graph you can write the equations just by looking at it.
 
Probably what you want for this is the fact that the integral is the area under the curve.

Given a graph for a(t), estimate the area under the curve from 0 to t for a number of different values of t. That will give the graph for v(t). It is probably enough to remember things like: if the graph of a(t) is above a=0, then v(t) is increasing, if below, then v(t) is decreasing. if the graph of a(t) is horizontal, then v(t) increases (or decreases) linearly with slope given by the a value.

Once you have a rough graph for v(t), x(t) is the area under that curve. Repeat the process to get a graph of x(t).
 

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