Grassmann variables and Weyl spinors

302021895
Messages
8
Reaction score
0
I just started studying supersymmetry, but I am a little bit confused with the superspace and superfield formalism. When expanding the vector superfield in components, one obtains therms of the form [itex]\theta^{\alpha}\chi_{\alpha}[/itex], where [itex]\theta[/itex] is a Grassmann number and [itex]\chi[/itex] is a Weyl vector.

I am aware that Grassmann numbers anticommute [itex]\{\theta_{\alpha},\theta_{\beta}\}=0[/itex], and that ordinary numbers commute with Grassmann variables. Do Weyl spinor components commute or anticommute with the Grassmann variables? ([itex]\{\theta_{\alpha},\chi_{\beta}\}=0[/itex] or [itex][\theta_{\alpha},\chi_{\beta}]=0[/itex]).
 
Physics news on Phys.org
Weyl spinor components are Grassman variables. As such they anticommute with other Grassman variables.

I'm not sure why you call the chi a "Weyl vector". The vector superfield V is not a vector, but it describes a vector multiplet and as such contains a field [itex]v_{\mu}[/itex] which is a spacetime vector.
 
Hi!
I have a similar problem: what is the result of a commutator/anticommutator like this?
[itex]\left\{ \left( \gamma^{\mu} \theta \right)_{\alpha} \partial_{\mu} , \frac{\partial}{\partial \bar{\theta}^{\beta} } \right\}[/itex]
Thank you
 
Use that the theta's (both the parameters and derivatives wrt them) anticommute and form an orthogonal basis for the fermionic part of superspace.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K