- #1
katewhitney
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"Consider a system of just two particles, with identical masses, orbiting in circles about their center of mass. SHow that the gravitational potential energy of this system is -2 times the total kinetic energy.
KE = 1/2 mv^2
U(potential) = -2U(kinetic)
grav. potential =
U=-GMm-r
we're supposed to set 1/2mv^2 to the rotational gravitational energy -- but I think i have the wrong equation and I don't know where to go from here...
Homework Equations
KE = 1/2 mv^2
U(potential) = -2U(kinetic)
grav. potential =
U=-GMm-r
The Attempt at a Solution
we're supposed to set 1/2mv^2 to the rotational gravitational energy -- but I think i have the wrong equation and I don't know where to go from here...