Gravitation: Object moving from infinity

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The discussion centers on determining the condition for a celestial body B to collide with another body A, focusing on the parameter σ, which is defined as a multiple of the radius R. The user initially attempts to derive σ by using Pythagorean theorem and energy conservation principles, but encounters issues with the presence of an additional constant term, n, in the final expression. Participants suggest that the approach should consider the trajectory of body B as a hyperbola with its closest approach (periapsis) equal to R, emphasizing that body B will not drop below escape velocity during its path. They recommend applying conservation laws, specifically conservation of angular momentum and energy, to simplify the problem. The discussion highlights the importance of understanding the dynamics of gravitational interactions in celestial mechanics.
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Homework Statement
There is a spherical celestial body A with the radius of 𝑅 and the mass of 𝑀. As
shown in figure, consider movement of a celestial body B of which relative
velocity at infinity is 𝑣∞ with respect to the celestial body A and the mass is
negligible compared to the celestial body A. At infinity, the celestial body B moves
in the horizontal direction shown in the Figure, and the distance from the straight
line which passes through the center of the celestial body A and is parallel to the
movement direction of the celestial body B

Express the condition of 𝜎 where the celestial body B collides against the
celestial body A
Relevant Equations
GM/R
Express the condition of 𝜎 where the celestial body B collides against the
celestial body ASo this is the original figure of the problem.

Screen Shot 2020-05-26 at 5.13.53 PM.png
This is my attempt at a solution

20200526_174657.jpg


Since I need to find σ, I have assumed sigma to be an multiple of the radius ## R ##. So, let ## \sigma = \lambda R ##, where ## \lambda ## is some constant term. I have also assumed that the object ## B ## comes into the gravitational influence of object ## A ## when its a horizontal distance of ## n \lambda R ## away (n is some other constant term)

So, using Pythagoras theorem, the distance of object B ## r = \sqrt{{(\lambda R)}^2 + {(n \lambda R)}^2} ##. Substituting ## \sigma ## back, this implies ## r= \sigma \sqrt{n^2 + 1} ##

So, my approach is when object is at a distance ## r= \sigma \sqrt{n^2 + 1} ##, its velocity is ## v_2 ##.This velocity should be less than the orbital velocity at distance ## r ## for it to collide with planet A.

This velocity can be calculated using conservation of energy.

At infinity, ## T_0 = \frac{1}{2}m{v_{\inf}}^2 ##.

At point ## v_2 ##, ## T_1 = \frac{1}{2}m{v_2}^2 - \frac{GMm}{r} ##

Solving this we get ## {v_2}^2 = {v_{inf}}^2 + \frac{2GM}{r} ##. Since ## v_2 < v_{orb} ##

$$ \Rightarrow {v_{inf}}^2 + \frac{2GM}{r} < \frac{GM}{r} $$.

$$ \Rightarrow {v_{\inf}}^2 < - \frac{GM}{r} $$

$$ \Rightarrow r < - \frac{GM}{{v_{\inf}}^2} $$

Substituting everything, I get a value for ## \sigma ## which has the constant term ## n ##. However, I'm not supposed to have ## n ## in the answer. What am I doing wrong?
 

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I see no advantage in considering that B is not always in A's gravitational field.
What conservation laws apply?
 
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It sounds like you are trying to find what is sometimes called the "impact parameter".

The path the object will follow is a hyperbola with the focus at the center of object A. I've modified the diagram to illustrate.
HYPERBOLA.gif

You are solving for the hyperbola where the periapsis ( Closest approach to the center of A) is equal to R.
Your assumption of the velocity ever being below orbital velocity is incorrect. At no point of it's trajectory will object B ever even drop below escape velocity.
 
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Janus said:
You are solving for the hyperbola where the periapsis ( Closest approach to the center of A) is equal to R.
The problem is much easier than that.
 
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It is an interesting exercise to do the derive the hyperbola, but my method (which I think is the same as @haruspex's method) just involves writing down two equations from two conservation laws and eliminating one variable.
 
Try using conservation of angular momentum as well as conservation of energy.
 

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