High School Gravitational acceleration in circular motion

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SUMMARY

The discussion centers on the concept of gravitational acceleration in the context of uniform circular motion, specifically addressing the value of 9.8 meters per second squared. Participants clarify that while centripetal acceleration is present, gravitational acceleration does not alter the speed of an object in circular motion; it affects the direction of the velocity vector instead. The formula for centripetal acceleration, a = v²/r, is highlighted, emphasizing the need to set specific values for speed (v) and radius (r) to achieve 9.8 m/s². The conversation also references the conical pendulum as a related topic for further exploration.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula, a = v²/r
  • Familiarity with the concept of gravitational acceleration (9.8 m/s²)
  • Basic knowledge of vector dynamics and velocity
  • Awareness of conical pendulum mechanics
NEXT STEPS
  • Research the dynamics of conical pendulums and their applications
  • Explore the relationship between gravitational force and centripetal force in circular motion
  • Study the effects of varying speed (v) and radius (r) on centripetal acceleration
  • Learn about vector decomposition in physics to understand changes in velocity
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of motion, particularly in circular dynamics and the interplay between gravitational and centripetal forces.

physicsmagician
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Hi guys, I have a question that is simple but I do not know how to answer that. It is the following, where does the acceleration of 9,8 meters per second squared go when We're dealing with uniform circular motion? I know that We have the centripetal acceleration that is a vector change, but the value of 9,8 I said, where did it go?
 
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a=\frac{v^2}{r}
You should set values of speed v and radius r to get a=9.8 m/sec^2.

If you are talking on sum of gravity force or acceleration and centrifugal force or acceleration, Conical pendulum https://en.wikipedia.org/wiki/Conical_pendulum might be of your interest.

 
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What do you mean "where does it go"? Are you asking why the speed doesn't change? If so, the point is that acceleration doesn't change speed, it changes velocity. In the particular case of circular motion it happens not to change the magnitude of the vector, that's all.
 
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