B Gravitational acceleration in circular motion

[physicsmagician]

Hi guys, I have a question that is simple but I do not know how to answer that. It is the following, where does the acceleration of 9,8 meters per second squared go when We're dealing with uniform circular motion? I know that We have the centripetal acceleration that is a vector change, but the value of 9,8 I said, where did it go?

 

[anuttarasammyak]

a=\frac{v^2}{r}
You should set values of speed v and radius r to get a=9.8 m/sec^2.

If you are talking on sum of gravity force or acceleration and centrifugal force or acceleration, Conical pendulum https://en.wikipedia.org/wiki/Conical_pendulum might be of your interest.

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[Ibix]

What do you mean "where does it go"? Are you asking why the speed doesn't change? If so, the point is that acceleration doesn't change speed, it changes velocity. In the particular case of circular motion it happens not to change the magnitude of the vector, that's all.