(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A small mass M and a small mass 3M are 3.60m apart. Where should you put a third small mass so that the net gravitational force on it due to the other two masses is zero?(From mass M)

2. Relevant equations

F = G(m1)(m2)/d^2

3. The attempt at a solution

I then tried solving the problem by setting the two unknown variables (the distance between the 3rd mass and 1st mass and the 3rd mass and the 2nd mass) like this:Code (Text):

I envisioned the problem to originally look like this:

[1M] [3M]

And adding in the 3rd mass I envisioned it to look something like this:

[1M] (1M) [3M]

x = Distance between [1M] and (1M)

3.60-x = distance between (1M) and [3m]

I was thinking this would give me an equation looking like this:

G[1M](1M)/x^2 = G(1M)[3M]/(3.60-x)^2

I tried solving this but it's not giving me the right answer... Should the right equation above be G(2M)(3M)/(3.60-x)^2 because of combined mass?

**Physics Forums - The Fusion of Science and Community**

# Gravitational attraction between 3 masses.

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Gravitational attraction between 3 masses.

Loading...

**Physics Forums - The Fusion of Science and Community**