∆KE if angle between force and displacement varies

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Homework Help Overview

The problem involves a block sliding along a frictionless surface while being pulled by a constant tension in a string over a pulley. The objective is to calculate the change in kinetic energy (∆KE) as the block moves from one position to another, considering the angle between the force and displacement varies during the motion.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to derive an expression for acceleration and velocity over time, but realizes the complexity of treating the angle as a constant. They seek to express the angle as a function of time.
  • Some participants suggest that time is not necessary for solving the problem and question the relationship between work done and kinetic energy.
  • There are discussions about the definition of work and how it relates to force and displacement, with participants exploring the mathematical representation of work.
  • Questions arise about expressing the angle in terms of position and the integral needed to compute work.

Discussion Status

The discussion is ongoing, with participants providing hints and clarifications about the relationship between work and kinetic energy. There is an exploration of how to express the angle in terms of position, indicating a productive direction in the conversation.

Contextual Notes

Participants are navigating the complexities of the problem, including the varying angle and its implications for calculating work and kinetic energy. There is a focus on definitions and relationships rather than specific numerical solutions.

patrykh18
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Homework Statement



A string is attached to a block that can slide along a frictionless horizontal surface aligned along the x axis. The left end of the string is pulled over a pulley of negligible mass and friction at a height of 1.3m so that the block slides from x1=3m to x2=1m. The tension in the string remains constant (25N). Calculate the ∆KE.

Homework Equations



W=F•x=|F||x|cosA where A is the angle
KE=0.5mv^2
∆KE= KE final- KE initial

The Attempt at a Solution



In my first attempt I got an answer of 30.49 J. What I did is I I said that ma=-25cosA so a=-(25cosA)/m
I integrated with respect to t. Since the velocity at x=3m is not stated I let it equal v0. So the integration constant was v0. I integrated v with respect to time. My integration constant was 3 as that was the original displacement. Next I found the time at which x=1m in terms of m (I knew the angle at that time using basic trigonometry). I took my value of time and plugged it back into equation for velocity.

After doing it I realized that obviously my answer is wrong as I treated cosA like a constant as I was intergrating. My problem is that i can't figure out the expression for A as a function of time.

I have attached below a diagram of the system. Any help will be much appreciated.

1507988661517-1730420136.jpg
 
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Hint: You do not need to compute the velocity or how the position depends on time. In fact, you do not need to involve time at all in this problem. What is the relation between the work done on the block and the difference in its kinetic energy?
 
Orodruin said:
Hint: You do not need to compute the velocity or how the position depends on time. In fact, you do not need to involve time at all in this problem. What is the relation between the work done on the block and the difference in its kinetic energy?

Well they are equal to each other. I am just not sure how to calculate the work done
 
What is the definition of work done?
 
Orodruin said:
What is the definition of work done?

Its the transfer of energy to or from an object due to the action of a force.
 
patrykh18 said:
Its the transfer of energy to or from an object due to the action of a force.
And how is it expressed in terms of the force and the displacement of the object?
 
Orodruin said:
And how is it expressed in terms of the force and the displacement of the object?
It's the dot product of the two
 
So in this case, what is the force on the block at a given position and how is it being displaced?
 
It is displaced in the negative x direction and the force in that direction is negative 25cosA
 
  • #10
So how can you express the angle in terms of the position? Can you give an expression for the integral you need to compute in order to find the work?
 
  • #11
Orodruin said:
So how can you express the angle in terms of the position? Can you give an expression for the integral you need to compute in order to find the work?
I suppose the angle can be expressed as Tan inverse of 1.3/x
 
  • #12
Or it can also be expressed as cos inverse of x/√x^2 +1.3^2
 

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