Gravitational field owing to a uniform circular plate

In summary, the problem is to find the gravitational field due to a thin uniform circular plate of radius a at a point R from the center, on the axis perpendicular to the plane of the plate. The solution involves using the equations F= GMm/r^2 and E=F/m, and integrating the force from each differential piece of mass on the vertical axis passing through the center. This will result in a negative sign in the final equation, which satisfies the requirement for the field to be on the vertical axis passing through the center.
  • #1
Dumbledore211
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1

Homework Statement



Show that the gravitational field due to thin uniform circular plate of radius a at point distant R from center and on the axis passing through the center and perpendicular to the plane of the plate is given by E= -2πGρ[1-R/(a^2+R^2)^1/2]

Homework Equations



F= GMm/r^2
E=F/m

The Attempt at a Solution


I really don't have any proper approach as to how I should go about this problem. How am I going to get a negative sign in the field created by the plate making sure the field is on the vertical axis passing through the center? Would be very helpful if any of you could drop a hint as to how I should start this problem as I am at a total loss with this one.
 
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  • #2
I'm not really sure what your confusion is. Your goal is to find the force per mass on an object which lies on a line that is perpendicular to the circle and passes through the center of the circle. Call the distance to the center of the circle R and integrate the force from each differential piece of mass (remembering that force is a vector) in which ever way you think is easiest.
 

1. What is a gravitational field?

A gravitational field is a region in space where objects with mass experience a force of attraction towards each other. It is created by the presence of mass and its strength is directly proportional to the mass of the objects and inversely proportional to the distance between them.

2. How is the gravitational field of a uniform circular plate calculated?

The gravitational field of a uniform circular plate can be calculated using the formula: g = (2GM)/(R√(R^2+h^2)), where g is the gravitational field strength, G is the gravitational constant, M is the mass of the plate, R is the radius of the plate, and h is the distance from the center of the plate to the point where the field is being measured.

3. What is the direction of the gravitational field owing to a uniform circular plate?

The direction of the gravitational field owing to a uniform circular plate is always towards the center of the plate. This means that any object placed anywhere on the surface of the plate will experience a force of attraction towards its center.

4. How does the gravitational field change as you move away from the plate?

The gravitational field strength decreases as you move away from the plate. This is because the force of attraction between two objects is inversely proportional to the square of the distance between them. Therefore, the farther away an object is from the plate, the weaker the gravitational field it experiences.

5. What are some real-life examples of a uniform circular plate creating a gravitational field?

One example is the Earth's gravitational field created by its mass and experienced by objects on its surface. Another example is the gravitational field created by a spinning disc, such as a CD or a vinyl record. This field can cause objects placed on the disc to move towards its center due to the centripetal force. Additionally, the gravitational field of a planet or star can also be modeled as a uniform circular plate, as long as the distance from the object's center is much greater than its radius.

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