Gravitational Field Strength Help

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SUMMARY

The gravitational field strength at an altitude of 220 km above Earth's surface is calculated using the formula g = Gm₂/d². In this case, G is 6.67 x 10-11 N.m²/kg², m₂ is 5.98 x 1024 kg, and d is 6.60 x 103 km, which must be converted to meters for accurate results. The correct gravitational field strength is approximately 9.18 N/kg, aligning closely with the textbook answer of 9.1 N/kg. A common error in this calculation is neglecting to convert kilometers to meters.

PREREQUISITES
  • Understanding of gravitational force equations, specifically Fg = mg and Fg = Gm₁m₂/d²
  • Knowledge of the gravitational constant, G = 6.67 x 10-11 N.m²/kg²
  • Familiarity with mass of Earth, m₂ = 5.98 x 1024 kg
  • Ability to convert units, particularly kilometers to meters
NEXT STEPS
  • Research the concept of gravitational field strength and its applications in physics
  • Learn about unit conversion techniques, especially for distance measurements
  • Explore the implications of altitude on gravitational force
  • Study the derivation and applications of Newton's law of universal gravitation
USEFUL FOR

Students studying physics, educators teaching gravitational concepts, and anyone interested in understanding gravitational field strength calculations in relation to altitude.

shootingrubbe
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Hello Everyone, I've been trying to get the answer to this problem for ages now and I just can't match my answer with the one in the back of the textbook. I hope you can let me know what I'm doing wrong.

Homework Statement


What is the gravitational field strength at a place 220 km above Earth's surface, the altitude of many piloted space flights.

Homework Equations


Fg = mg
Fg = Gm₁m₂/d²

The Attempt at a Solution


d = 6.60 x 10³ km
G = 6.67 x 10-¹¹ N.m²/kg²
m₂ = 5.98 x 10²⁴ kg
g = ? N/kg

Fg = mg = Gm₁m₂/d²
mg/m = Gm₁m₂/d²/m
g = Gm₂/d²
g = (6.67 x 10-¹¹ N.m²/kg²)(5.98 x 10²⁴ kg)/((6.60 x 10³ km)²)

And when I do this I always get the wrong answer when I compare it with the one in the back of the textbook. The answer in the back of the textbook is 9.1 N/kg [down].

If anyone here could please help me with this, that would be great.

Thanks.
 
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Equation looks fine to me, I solved it and got 9.18 N/kg
what did you get?
 
Thanks, I guess I was doing it right, I just forgot to convert the distance into meters.
 
oh of course, how could I overlook that. I didn't follow your equation, I did it myself. I should have checked your equation more thoroughly!
 

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