Gravitational Field Variation of Disc Orbitating Earth

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SUMMARY

The discussion revolves around a hypothetical scenario where the moon is modeled as a disc orbiting the Earth, with specific dimensions related to its mass and distance from the Earth's center of mass. Participants emphasize the need for an algebraic expression to determine the gravitational field variation at both the poles and the Earth's center of mass. The conversation highlights the importance of adhering to forum guidelines, particularly regarding homework submissions and the necessity of providing an initial attempt at solving the problem.

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LeoPedranjo
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Moved from another forum, so homework template missing
Hey guys, take a look at this question if you may

Suppose the moon, instead of a sphere, is a disc orbitating the Earth ( the moon's total mass is equal to the disc's total mass), the intern radius of the disc is equal to half the distnce between moon and Earth's center of mass and the external radius equals double of the distance between moon and Earth's CM. Find an algebric expression that determines: a) the variation in the gravitacional field due to the disc in the north pole or south pole. b) the variation in the gravitational field due to the disc in Earth's center of mass.

That is the whole question. Will there be any effect on the poles at all? Considering that the Earth will pull the disc to its center...

Ty
 
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Is this a homework question or just a random exercise? If it's hw, it should be posted on the homework forum.
 
UncertaintyAjay said:
Is this a homework question or just a random exercise? If it's hw, it should be posted on the homework forum.
Its hw, sorry!
 
LeoPedranjo said:
Its hw, sorry!

OK please repost in the appropriate homework section and use the homework template :smile:Dave
 
You will have to give an attempt at a solution to get help with this problem.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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