Gravitational force acting between objects

[Abu]

Homework Statement

4 10kg objects are located at the corners of a rectangle sides 2 meters and 1 meter. Calculate the magnitude of gravitational force on 1 due to the other 3.

(Same sort of idea)
3 1kg objects are located at the corners of an equilateral triangle of side length 1 meter

Homework Equations

F= Gm*M/r^2

The Attempt at a Solution

So, let's say that I am finding the gravitational force on 1 for the rectangle (labeling the rectangle clockwise starting from the top right). My first idea was to find the gravitational force between 1 and 4 which would be directly to the left.
Then I wanted to find the gravitational force between 1 and 2 which would be directly below the rectangle. Then I wanted to find the gravitational force between 1 and 3, which would be directly diagonal from 1.

So here are my calculations for those, in order:
Force on 1 due to 4: 6.67*10^-11 10*10/2^2 = 1.67*10^-9
Force on 1 due to 2: 6.67*10^-11 10*10/1^2 = 6.67*10^-9
Force on 1 due to 3: 6.67*10^-11 10*10/√5^2 = 1.334*10^-9

But I don't know what to do from here because my answer is wrong. Am I supposed to be adding these 3 forces together, or is there a vertical and horizontal component I am missing or something?

I am assuming that if I understand how to do the rectangle one, I'll be able to do the triangle one. I may need help with that one too though
If my question isn't clear, I'll be happy to clarify it for you. Thank you.

 

[haruspex]

Am I supposed to be adding these 3 forces together,

Yes, but as vectors. Do you know how to add vectors?

 

[Abu]

Yes, but as vectors. Do you know how to add vectors?

Do you mean you want me to split the forces into x and y components? like 1 to 4 would be in the x direction and 1 to 2 would be in the y direction?

 

[haruspex]

Do you mean you want me to split the forces into x and y components? like 1 to 4 would be in the x direction and 1 to 2 would be in the y direction?

Yes, and what about 1 to 3?

 

[Abu]

Yes, and what about 1 to 3?

Okay so I found the angle with tanΘ=1/2, then Θ = 26.5 degrees
I found the component of 1 to 3 in the X direction to be:
cos26.5= x/1.334*10^-9 and it equals 1.193*10^-9

For the component of 1 to 3 in the Y direction I did:
sin26.5 = y/1.334*10^-9 and it equals 5.95*10^-10

and then adding the x and y components together now would make

X
1.67*10^-9 + 1.193*10^-9 = 2.862*10^-9
Y
6.67*10^-9 + 5.95*10^-10 = 7.3*10^-9

And then imagining this as a triangle with X and Y components, I just use
F = √(2.862*10^-9)^2 +(7.3*10^-9)^2
F = 7.8*10^-9 Newtons

Is this correct? Sorry for the late responses.
If so I think I'm going to try the triangle one next.

 

[haruspex]

6.67*10^-9 + 5.95*10^-10 = 7.3*10^-9

I would keep one more digit of precision here. Other than that, this all looks right now.

 

[Abu]

I would keep one more digit of precision here. Other than that, this all looks right now.

Thank you for your help, I appreciate it.