Gravitational Force of Bowling & Billiard Balls - Homework

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Homework Help Overview

The problem involves calculating the gravitational force between a bowling ball and a billiard ball, both treated as uniform spheres. The original poster expresses confusion regarding the correct use of the radii in the gravitational force equation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the appropriate method for calculating the distance between the centers of the two spheres, questioning whether to sum the radii. There is also a focus on the accuracy of the gravitational force calculation and the values used in the formula.

Discussion Status

The discussion is ongoing, with participants providing feedback on calculations and suggesting corrections to values used in the gravitational force equation. There is no clear consensus yet, as different interpretations of the problem setup are being explored.

Contextual Notes

Participants note discrepancies in numerical values and emphasize the importance of using correct entries in calculations. There is mention of homework constraints that may affect how the problem is approached.

RKNY
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Homework Statement


A bowling ball (mass = 7.2 kg, radius = 0.13 m) and a billiard ball (mass = 0.40 kg, radius = 0.028 m) may each be treated as uniform spheres. What is the magnitude of the maximum gravitational force that each can exert on the other?

Homework Equations


F = G(m1m2/r^2)

The Attempt at a Solution


Im confused about the radius portion of the problem. Shouldn't you add up the radius of both (0.028 + 0.13) and use that answer in the equation?
 
Last edited:
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I would think that's as close as the two could come together and therefore the greatest force would be generated. You seem to imply that this is not the case?
 
denverdoc said:
I would think that's as close as the two could come together and therefore the greatest force would be generated. You seem to imply that this is not the case?

F = G x m1 x m2 / r^2

F = (6.67 x 10^-11) x (7.2) x (0.40) / (0.148) x 2

F = .000000001

Doesn't seem to be right when I go and check it.
 
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you have .44 above when the problem states .4, and .148 instead of .158 as you suggested using in the denom. maybe follow suit and go to bed as I intend to now.
 
Last edited:
denverdoc said:
you have .44 above when the problem states .4, and .148 instead of .158 as you suggested using in the denom. maybe follow suit and go to bed as I intend to now.

sorry, I went back and changed everything. Now everything seems to be the way I attempted it.
 
well the denominator still shows 0.148, when its 0.158; also make sure to use exponential entry with your calculator; if it doesn't support such, then use the windows free calculator--use the more advanced of the two available. I get something like 7.7e-9
 

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