Gravitational force, Speed, and period of a Satellite.

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SUMMARY

The discussion focuses on calculating the gravitational force, speed, and orbital period of a satellite with a mass of 300 kg, positioned 5.00 x 107 m above Earth's surface. The gravitational force was calculated to be 38 N, while the speed was determined to be 9,572,517 m/h, and the orbital period was found to be 37 hours. Participants noted discrepancies in the speed and period calculations, emphasizing the importance of using consistent units, particularly converting the period into seconds for accuracy.

PREREQUISITES
  • Understanding of gravitational force calculations using the formula Fg = GME*m/(r + rE)
  • Familiarity with orbital mechanics, specifically the period of a satellite using T2 = [4π2/G(ME + m)]*(r + rE)3
  • Knowledge of unit conversions, particularly between hours and seconds
  • Basic principles of circular motion and satellite dynamics
NEXT STEPS
  • Learn about gravitational force calculations in different orbital scenarios
  • Study the implications of unit consistency in physics calculations
  • Explore the relationship between satellite mass and orbital period
  • Investigate the characteristics of geostationary satellites and their orbital parameters
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and orbital dynamics, as well as educators seeking to clarify satellite motion concepts.

Imuell1
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Homework Statement


A satellite that has a mass of 300 kg moves in a circular orbit 5.00 X 107 m above Earth's surface. (a) What is the gravitational force on the satellite? (b) What is the speed of the satellite? (c) What is the period of the satellite?



Homework Equations


Fg= GMEm/(r+rE
T2= [4pi2/G(ME+m)]*(r+rE)3


The Attempt at a Solution


Fg= 38N
T=37 hours
V=9572517 m/h

I think the gravitational force might be right but the speed and period seem to be ridiculously too large.
 
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37 is not so much :D
a broadcasting satellite ,which has period of 24 hours around earth(like the Earth around it self!) has a distance of 3.6*10^7 meters from the surface of the Earth AFAIK.
But didnt get the same V as You did,did You write T as seconds?(37*60*60
EDIT1:
Oh I did, didn't see Your units ,You better solve it with seconds, and not m/h
EDIT2:
How did the mass of the satellite get to the equation of period?
 
Last edited:

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