Gravitational Forces of binary star

Click For Summary
SUMMARY

The discussion centers on calculating the speed of a comet at the midpoint of a binary star system, where each star has a mass equal to that of the Sun and is separated by 1x10^12 meters. The user, nitro, initially set up the problem using gravitational force equations and attempted to derive the acceleration of the comet. Another participant suggested applying the work-energy theorem, integrating the gravitational force over the distance from infinity to the midpoint to find the comet's kinetic energy and speed using conservation of energy principles.

PREREQUISITES
  • Understanding of gravitational forces and Newton's law of universal gravitation
  • Familiarity with the work-energy theorem in classical mechanics
  • Knowledge of integration techniques in calculus
  • Basic concepts of binary star systems and their dynamics
NEXT STEPS
  • Study gravitational force calculations in binary star systems
  • Learn about the work-energy theorem and its applications in astrophysics
  • Explore integration techniques for solving physics problems
  • Investigate the conservation of energy in celestial mechanics
USEFUL FOR

Astronomy students, astrophysicists, and anyone interested in gravitational dynamics and the behavior of celestial bodies in binary star systems.

nitrostar
Messages
6
Reaction score
0
I have this problem:

The question says: A binary star system has two stars, each with the same mass as our sun, separated by 1x10^12m. A comet is very far away and essentially at rest. Slowly but surely, gravity pulls the comet toward the stars. Suppose the comet travels along a straight line that passes through the midpoint between the two stars. What is the comet's speed at the midpoint?

I set up the system like this:
Code:
      c
    / | \
   /  |  \
  /   |   \
bs1---m---bs2

where c=comet
m = midpoint
bs1 and bs2 are the binary stars

We know Fxnet=0
And Fynet = 2*Fybs2
Fbs2=mMG/r^2
if we set up an angle @ between the commet and bs2 we can deduce that
sin@=5*10^11/r
so
r=5*10^11/sin@

Fbs2=mMG/(5*10^11/sin@)

Fybs2=Fbs2*cos@
Fybs2=mMG*sin@*cos@/(5*10^11)


Fynet=(2*mMG/(5*10^11))*int(sin@cos@d@,0,pi/2)
Fynet=m*2.655*10^8=ma
a=2.655*10^8

But now what??
Am i doing things right?

Thank you very much!
nitro
 
Physics news on Phys.org
If one measures the distance of the comet from the midpoint between the two stars, r, up to the point where it currently is, then the resulting force from the two stars points from the comet towards this midpoint and is given by twice the component of one of these forces, say F_S, along r. This results in an equation for the resultant force in terms of G,M,m,r\ and\ d where d is half the distance between the stars. Apply the work kinetic energy theorem - that is integrate this force over r for r from infinity to zero. This gives you the kinetic energy when the comet reaches the midpoint between the two stars.
 
i solved it using potential/kinetic energy and the law of conservation of energy!

Thank you very much though!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
10
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K