Gravitational Potential and Satellite Motion

Click For Summary
SUMMARY

The discussion focuses on calculating the mass of a star based on the orbital characteristics of a planet. The planet orbits the star with a period of 4.44x107 seconds and is located 4.28x1011 meters away. Participants suggest using Kepler's third law and gravitational equations, specifically F = mv2/R and τ2 = (4π2a3)/(G(M+m)), to derive the star's mass. The consensus emphasizes that the mass of the planet can be neglected in this calculation.

PREREQUISITES
  • Understanding of Kepler's laws of planetary motion
  • Familiarity with gravitational force equations
  • Knowledge of orbital mechanics
  • Basic proficiency in algebraic manipulation of equations
NEXT STEPS
  • Study Kepler's Third Law of Planetary Motion in detail
  • Learn about gravitational force calculations using Newton's laws
  • Explore the implications of orbital mechanics on satellite motion
  • Investigate the application of G (gravitational constant) in astrophysical calculations
USEFUL FOR

Astronomers, astrophysics students, and anyone interested in celestial mechanics and the calculation of stellar masses based on orbital data.

kingyof2thejring
Messages
82
Reaction score
0
Astronomers observing a distant solar system have noticed a planet orbiting a star with a period of 4.44x107 s. The distance from the planet to the star is 4.28x1011 m. Calculate the mass of the star, in kg.

ihave used v = 2*pi*r/T and v=(2Gm/r)^1/2
i get 8.75e18
is this the way to calculate m
thanks in advance
 
Physics news on Phys.org
The more logical thing to do (imho) is:

[tex]F = \frac{mv^2}{R} = \frac{GMm}{R^2}[/tex]

Which simplify into Kepler's law, with the subsitution: [tex]v = \frac{2\pi R}{T}[/tex]
 
Why are you finding velocity if the problem asked for the mass of the star?

You can use Kepler's third law, or:

[tex]\tau^2=\frac{4 \pi^2 a^3}{G(M+m)}[/tex]
Unless the planet is very, very big for a planet, it can be disregarded, eliminating the little m from the equation. The rest is rearranging the equation to solve for big M.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
8
Views
2K