m.g.h = (GMm)/r how can we prove that mgh is potential energy and both equal to that?
Jun 12, 2020 #1 marialovesphysics 2 0 m.g.h = (GMm)/r how can we prove that mgh is potential energy and both equal to that?
Jun 12, 2020 #2 sysprog 2,613 1,783 Prof. Richard Muller discusses this in the first answer here: https://www.quora.com/Whats-the-dif...versus-mgh-for-gravitational-potential-energy
Prof. Richard Muller discusses this in the first answer here: https://www.quora.com/Whats-the-dif...versus-mgh-for-gravitational-potential-energy
Jun 13, 2020 #3 mpresic3 377 267 You kind of have to watch out. when you use U = mgh, your zero of potential energy is at h = 0. when you use the other equation, the zero of potential energy is at r = infinity. m gh is based on a constant gravity (or flat Earth assumption) good for local physics the other equation is based on a inverse square gravity. good when far from Earth center.
You kind of have to watch out. when you use U = mgh, your zero of potential energy is at h = 0. when you use the other equation, the zero of potential energy is at r = infinity. m gh is based on a constant gravity (or flat Earth assumption) good for local physics the other equation is based on a inverse square gravity. good when far from Earth center.