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Gravitational Potential Energy of a box

  1. Feb 12, 2010 #1
    1. The problem statement, all variables and given/known data

    a 18.5 kg box is slid up a 5.6 m long ramp that makes an angle of 33 degrees with the floor. What is the gravitational potential energy of the box relative to the floor?

    m = 18.5 kg
    d = 5.6 m
    http://musr.physics.ubc.ca/~jess/symbols/Theta.gif = 33°
    PEg = ?

    2. Relevant equations

    Eg = mgh

    I think. haha

    3. The attempt at a solution

    I have absolutely no idea. I am hoping someone on here could get me started with this question, not give me the answer, but just get me started. Thanks.
    Last edited by a moderator: Apr 24, 2017
  2. jcsd
  3. Feb 12, 2010 #2
    You are right about [tex]E_{gp}=mgh[/tex]. Height [tex]h[/tex] is the only problem and it can easily be obtained by using trigonometry.
  4. Feb 12, 2010 #3
    Ahh, silly me! Thank you very much! Have a nice day :)
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