Gravitational Potential Energy - Orbits

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Homework Help Overview

The discussion revolves around calculating the gravitational acceleration of a satellite in a circular orbit 655 km above Earth's surface, touching on concepts of gravitational potential energy and forces acting on the satellite.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between gravitational potential energy and gravitational force, questioning whether to equate different equations. There is discussion about the role of centripetal force in orbital motion and the necessity of the satellite's mass in calculations.

Discussion Status

Some participants have offered guidance on focusing on forces rather than potential energy, suggesting that the mass of the satellite may not be needed for calculating acceleration. Multiple interpretations of the problem are being explored, with no explicit consensus reached.

Contextual Notes

Participants note that the equation for gravitational potential energy may not apply in this context due to the variable gravitational field at the height of the satellite's orbit.

Nicolaus
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Homework Statement


A satellite is in a circular orbit 655km above Earth's surface. Determine the magnitude of the gravitational acceleration at this height.


Homework Equations


Eg=mgh
Eg=-GMm/r


The Attempt at a Solution


Would I just set the aforementioned eqations equal to each other and re-arrange to solve for g? I would also have to solve for the change in Eg, as well, right?
 
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Nicolaus said:
Would I just set the aforementioned eqations equal to each other and re-arrange to solve for g?
No. Instead of potential energy, think in terms of forces and acceleration. What is the gravitational force on the satellite. (Tip: Don't be so quick to plug in numbers.)
 
Well, it's also experiencing a centripetal force. If we set Fc=Fg, we can get the velocity of the orbit, but, other than that, I'm not sure how to do this without the mass of the sat.
 
Nicolaus said:
Well, it's also experiencing a centripetal force. If we set Fc=Fg, we can get the velocity of the orbit, but, other than that, I'm not sure how to do this without the mass of the sat.
You won't need the mass--just call it 'm'. When you calculate the acceleration, it will drop out.

What is Newton's law of Universal Gravity?
 
Got it - I was overthinking a rather simple question..., thanks.
 
Also, E=mgh only works for constant gravitational fields. i.e. at the surface of a very large mass (like the Earth).
 

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