Gravitational Potential Energy: Two Neutron Stars

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Homework Help Overview

The problem involves two neutron stars separated by a significant distance, with a focus on calculating their velocities as they move towards each other due to gravitational attraction. The subject area includes gravitational potential energy and kinetic energy in the context of astrophysics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply conservation of energy and momentum to find the velocities of the neutron stars at different separations. Some participants question the treatment of potential energy, particularly whether it should be summed for both stars or considered as a single interaction term.

Discussion Status

Participants are actively discussing the correct formulation of gravitational potential energy in the context of the two-star system. There is acknowledgment of misunderstandings regarding the potential energy terms, and clarification has been provided regarding the interaction between the stars.

Contextual Notes

There is a focus on the assumptions made about the potential energy of the system and how it relates to the forces acting between the two neutron stars. The original poster's calculations are based on specific values for mass and distance, which may influence the discussion.

ArticMage
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Homework Statement


Deep in space, two neutron stars are separated (center-to-center) by a distance of 18 X 106 km apart. Neutron star A has a mass of 153 X 1028 kg and radius 52000 m while the neutron star B has a mass of 159 X 1028 kg and radius 72000 m. They are initially at rest with respect to each other.

a) With respect to that rest frame, how fast are the stars moving when their separation has decreased to one-half its initial value

b) How fast are each moving the instant before they collide?

The Attempt at a Solution


a) I set this up as follows.
Uia + Uib = Kfa + kfb +Ufa + Ufb

where U is potential energy and K is kinetic.

So i get -2*Ma*Mb*G/R = .5Ma*Va^2 + .5Mb*Vb^2 - 2Ma*Mb*G/R/2

Using conservation of momentum i get Ma*Va=Mb*Vb So Va=Mb*Vb/Ma
sub that in the above equation and solve for Vb I end up with somthing like sqrt( 2*(-2Ma*Mb*G/R +2Ma*Mb*G/R/2) / (Mb^2/Ma + Mb) ) = Vb
i get 105455 m/s and its wrong.
btw i am using 18^9 m for radius

for part b i would do a similar thing except set the radius for each equation equal to the radius for the planets for the final potential energy. I haven't tried this yet because if the first doesn't work I assume I am doign it wrong.
 
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You are wrong with the potential energy term: The stars interact and the potential energy of the whole system is just -G*Ma*Mb/R. Do not multiply by 2.

ehild
 
OK thanks that did it.

What i was doing was -G*Ma*Mb/R as the gravitation pot energy for star a then the same equation for star b, and since they are the same i just did 2* that. I am not really clear on why I wouldn't have to do that. Since both have potential energies due to the other don't they?
 
You would be right if there were two separate forces acting on both, for example from a third very big star. But they interact and there is a potential energy assigned to this interaction. Think: The potential energy is the negative of the work required to separate the stars from distance R to infinity. Pretend that one of them is fixed. You need GMaMb/R work to move one star to infinite distance from the fixed one, but then they are completely separated, there is no force between them any more.

ehild
 

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