Gravity and superpostion of two spheres

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SUMMARY

The discussion centers on calculating the gravitational force exerted by a hollowed-out lead sphere on a smaller sphere. The lead sphere has a radius of 4.6 m and an initial mass of 245 kg. Participants identified inconsistencies in the mass calculations based on the sphere's dimensions and lead density. The correct approach involves calculating the gravitational force using the formula F = F1 - F2, where F1 is the force of the full sphere and F2 is the force of the hollow sphere, while also considering the mass ratio of approximately 1 to 7.5.

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  • Understanding of gravitational force calculations
  • Familiarity with the concept of hollow spheres in physics
  • Knowledge of density and volume calculations
  • Proficiency with scientific calculators, such as the HP 300s+
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  • Study the gravitational force formula F = G(m1*m2)/r^2 in detail
  • Learn about the properties of hollow spheres and their effects on gravitational calculations
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This discussion is beneficial for physics students, educators, and anyone involved in gravitational force calculations, particularly those dealing with hollow objects and density-related problems.

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Homework Statement


The figure shows a spherical hollow inside a lead sphere of radius R = 4.6 m; the surface of the hollow passes through the center of the sphere and “touches” the right side of the sphere. The mass of the sphere before hollowing was M = 245 kg. With what gravitational force does the hollowed-out lead sphere attract a small sphere of mass m = 20 kg that lies at a distance d = 14 m from the center of the lead sphere, on the straight line connecting the centers of the spheres and of the hollow?
20150719_171355_zps0voqohjg.jpg

Homework Equations

The Attempt at a Solution


20150719_194518_zpscns6hjbm.jpg


when i find the mass of the "hollowed out" sphere its much larger than the larger sphere. I don't know how else to approach this problem.
 
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The mass of the sphere is inconsistent with its given diameter and the density of lead. I would ignore the given "lead" and calculate the density based on the given size and mass.
 
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mfb said:
The mass of the sphere is inconsistent with its given diameter and the density of lead. I would ignore the given "lead" and calculate the density based on the given size and mass.
I updated my original photo with my calculations. Would the total force be the force of the full sphere minus the force of the "hollow" sphere? F=F1-F2? I got the wrong answer not sure where i went wrong.
 
Your volume and density calculations don't look right to me. Can you recheck them?
 
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gneill said:
Your volume and density calculations don't look right to me. Can you recheck them?
Thank you! I am having problem getting adjusted to an hp 300s+, I often have to double check its picking up all the buttons i press.
 
J-dizzal said:
I updated my original photo with my calculations. Would the total force be the force of the full sphere minus the force of the "hollow" sphere? F=F1-F2?
Right (if you take both F1 and F2 to be positive).
A quick check: is your mass ratio 1 to 8?
The ratio of forces should be a bit smaller than that (1 to 7.something or 6.something) as the smaller sphere is a bit closer. If that is not true, something is wrong.
 

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