GRE Test Question Homework: Is (n^*)^* = n?

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Homework Help Overview

The problem involves a GRE practice question regarding a mathematical expression defined by the operation n^* = 32 - n. Participants are tasked with determining the relationship between (n^*)^* and n, with the answer key suggesting they are equal.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of the operation n^* and its implications for evaluating (n^*)^*. There is a focus on understanding the transformation of values through the defined operation.

Discussion Status

Some participants are seeking clarification on the operation represented by the asterisk and how it applies to the values derived from n. There is an acknowledgment of confusion regarding the nature of the operation, with guidance provided on its meaning.

Contextual Notes

There is a noted misunderstanding about the nature of the operation, with initial assumptions about it being exponential rather than a subtraction operation from 32. This has led to questions about how to evaluate the expressions correctly.

Xkaliber
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Homework Statement



Hi,
I was doing some GRE practice tests and came across this question:

for all number n, n^*=32-n (apparently where the asterisk is an exponent)

They then give me two values, which are (n^*)^* and n, and I am to say whether choice 1 is a greater value than choice 2, choice 2 is a greater value than choice 1, the two values are equal, or there is not enough info to determine. The answer key says they are equal. This means given the above equation, (n^*)^* = n

I can't see how this is true... Anyone care to explain? Thanks
 
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Let n^*=32-n=m. Then, (n^*)^*=m^*. Can you evaluate m^*?
 
cristo said:
Let n^*=32-n=m. Then, (n^*)^*=m^*. Can you evaluate m^*?

I'm not sure. Is there some way you want me to rewrite this? m^*=(32-n)^*
 
Xkaliber said:
I'm not sure. Is there some way you want me to rewrite this? m^*=(32-n)^*

Yes. The star is shorthand for the operation that "subtracts a given number from 32." In the case of m^*, the given number is 32-n. What is the result when you apply * to that?
 
lol, that was easy. I had in my mind that * was some sort of exponential value, not a more general operator. Thanks
 

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