Is x^y the Greatest Common Divisor of (5x+3y) and (13x+8y)?

[mtayab1994]

Homework Statement

prove that: x^y=(5x+3y)^(13x+8y)

Homework Equations

The Attempt at a Solution

Can I say that x^y divides both 5x+3y and 13x+8y and go on from there or what?

Then in case one u could multiply 5x+3y by 13 and 13x+8y by 5 and do the difference and you'll get that x^y divides y

Case 2: multiply 5x+3y by 8 and 13x+8y by 3 and then we get x^y divides x.

And from case 1 and case 2 we can conclude that x^y=(5x+3y)^(13x+8y).

Note that ^ stands for the greatest common divisor.

 

[HallsofIvy]

I strongly recommend that you NOT try to prove things that are not true!

Now, what is the problem really? For one thing, 8^{21} is not equal to 1.

Are you trying to prove that x^y is the greatest common divisor of (5x+ 3y)^{13x+ 8y}? Unfortunately, that's still not true. 13^{34}]/itex] is not divisible by 2.

 

[mtayab1994]

I strongly recommend that you NOT try to prove things that are not true!

So that is not true or what?

 

[Joffan]

Is this the question?:
Prove that the greatest common divisor of 5x+3y and 13x+8y is the same as the greatest common divisor of x and y.

or in notation I would understand:

Prove that gcd(5x+3y,13x+8y) = gcd(x,y)

And I suggest applying Euclid's algorithm to the polynomials on the left.

 

[mtayab1994]

Is this the question?:
Prove that the greatest common divisor of 5x+3y and 13x+8y is the same as the greatest common divisor of x and y.

or in notation I would understand:

Prove that gcd(5x+3y,13x+8y) = gcd(x,y)

And I suggest applying Euclid's algorithm to the polynomials on the left.

Yes I've solved it already thank you.

 

[Joffan]

Good... I hope your solution looked something like:


Since $\text{gcd}(m,n) = \text{gcd}(m-n,n)$,
<br /> \begin{align}<br /> \text{gcd}(13x+8y,5x+3y) &amp;= \text{gcd}(8x+5y,5x+3y)\\<br /> &amp;= \text{gcd}(3x+2y,5x+3y)\\<br /> &amp;= \text{gcd}(5x+3y,3x+2y)\\<br /> &amp;= \text{gcd}(2x+y,3x+2y)\\<br /> &amp; \dots<br /> \end{align}<br />etc.