Ground State of Quantum System: l=0?

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SUMMARY

The ground state of a quantum system typically corresponds to the lowest quantum numbers, specifically for systems governed by radial potentials. In the case of a finite 3-D potential well, the ground state indeed corresponds to l=0, as established in Griffiths' problem 4.9, which requires solving the radial equation with l=0. This configuration represents a spherical symmetry, which is associated with the lowest energy state in quantum mechanics.

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Homework Statement



Is it generally true that the ground state of a given quantum system corresponds to the lowest quantum numbers? For instance, is it generally true that the ground state of a system governed by a radial potential always corresponds to l=0? If not, how do we know, in particular, that the ground state of the finite, 3-D potential well corresponds to l=0? Griffiths seems to implicitly assume this fact in one of his problems (4.9): "Find the ground state (of the 3-D finite spherical well) by solving the radial equation with l=0."

Homework Equations





The Attempt at a Solution

 
Last edited:
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Here is a hint, l = 0 corresponds to a spherical configuration, which is usually the lowest eneergy state.
 

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