Group like terms factoring problem

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SUMMARY

The discussion focuses on the algebraic expression (x-y+2√x-2√y)/(√x-√y) and the process of factoring it. The user successfully grouped like terms to arrive at (x+2√x-y-2√y)/(√x-√y) and factored out √x and -√y. The challenge arose in simplifying the expression further, where the correct next step involves recognizing that x-y can be expressed as (√x+√y)(√x-√y). This insight allows for a cleaner simplification of the expression.

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kuahji
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(x-y+2[tex]\sqrt{x}[/tex]-2[tex]\sqrt{y}[/tex])/([tex]\sqrt{x}[/tex]-[tex]\sqrt{y}[/tex])

The first thing I did was group like terms
(x+2[tex]\sqrt{x}[/tex]-y-2[tex]\sqrt{y}[/tex])/([tex]\sqrt{x}[/tex]-[tex]\sqrt{y}[/tex])

Then from the liked terms I factored out a [tex]\sqrt{x}[/tex] & -[tex]\sqrt{y}[/tex]

(([tex]\sqrt{x}[/tex])([tex]\sqrt{x}[/tex]+2)-([tex]\sqrt{y}[/tex])([tex]\sqrt{y}[/tex]+2))/([tex]\sqrt{x}[/tex]-[tex]\sqrt{y}[/tex])

Here is where I get stuck. The next step should be, (([tex]\sqrt{x}[/tex]-[tex]\sqrt{y}[/tex])([tex]\sqrt{x}[/tex]+[tex]\sqrt{y}[/tex]+2)/([tex]\sqrt{x}[/tex]-[tex]\sqrt{y}[/tex])

However I'm just unsure how to jump to that next step.
 
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I think you want to use x-y=(sqrt(x)+sqrt(y))*(sqrt(x)-sqrt(y)).
 


Thanks, that works out much nicer.
 

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