1. The problem statement, all variables and given/known data A patient comes into the hospital for a bone scan and is injected with a dye containing Tc-99m. The half-life of Tc-99m is 6.03 h. What fraction of the original technetium will remain the patient 36 h after the procedure if radioactive decay is the only means by which it is removed? 2. Relevant equations 3. The attempt at a solution Af = Ao (1/2)t/h Af = 99 (1/2)36/6.03 Af = 1.579214746 1.57921476 / 98 = 0.016 0.016 x 100 = 1.6 % I am getting 1.6 % but the answer key states the answer as 0.016 %. What am I doing wrong. Is the m after Tc-99m play a role in this that I'm missing?