How to Calculate Initial Radioactive Activity for Patient Treatment?

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SUMMARY

The discussion focuses on calculating the initial radioactive activity required for a patient treatment involving a radioactive sample with a half-life of 83.61 hours. The target activity for irradiation is specified as 7.0 x 10^8 Bq over a duration of 24 hours. To determine the initial activity, participants emphasize using the decay constant formula, λ = ln(2)/T1/2, and the equation N = N0e^(λt) for accurate calculations.

PREREQUISITES
  • Understanding of radioactive decay and half-life concepts
  • Familiarity with the decay constant calculation
  • Knowledge of exponential functions and their applications in physics
  • Proficiency in using natural logarithms in calculations
NEXT STEPS
  • Study the derivation and application of the decay constant in radioactive decay problems
  • Learn how to apply the exponential decay formula N = N0e^(λt) in practical scenarios
  • Explore examples of radioactive decay calculations in medical treatments
  • Investigate the implications of half-life on patient safety and treatment efficacy
USEFUL FOR

This discussion is beneficial for students in physics or medical physics, healthcare professionals involved in radiation therapy, and anyone interested in the practical applications of radioactive decay in medical treatments.

soul5
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Homework Statement



Ok so I'm doing this practise problem but I have no clue what to do.

"A radioactive sample intended for irradiation of a hospital patient is prepared
at a nearby lab. The sample has a half-life of 83.61 h. What should it's initial activity be if it's activity is to be 7.0 X 10 ^ 8 Bq when it is used to irradiate the patient for 24 h?


Homework Equations




T 1/2 = Ln2/λ

N = N0e^λt


The Attempt at a Solution



Would you just do this?


N = 7.0 X 10 ^ 8 Bq e ^(83.61 - 24)

?

please help
 
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soul5 said:
Would you just do this?


N = 7.0 X 10 ^ 8 Bq e ^(83.61 - 24)

?

please help


Unfortunately not, start with

T1/2 = ln2/lambda
lambda = ln2/(T1/2)

and try again. Hope this helps :smile:
 

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